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Default/Overridable content for Aurelia template (template parts)


Default/Overridable content for Aurelia template (template parts)

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Default/Overridable content for Aurelia template (template parts)
Tag : javascript , By : omaidog
Date : November 24 2020, 09:00 AM

hope this fix your issue Use the "template parts" feature. More info here (search for "template parts").
pager.html
<template>
  <div class="pager-container">
    <button type="button" click.delegate="gotoBeginning()">
      <template replaceable part="goto-beginning-button-content">|<</template>
    </button>
  </div>
</template>
<template>
  <require from="./components/pager/pager"></require>
  <pager>
    <template replace-part="goto-beginning-button-content">
      <i class="glyphicon glyphicon-step-backward"></i>
    </template>
  </pager>
</template>

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Why the template with default template arguments can't be used as template with less template argument in Template Templ


Tag : cpp , By : Ernie Thomason
Date : March 29 2020, 07:55 AM
it helps some times From the standard (see 14.3.3 paragraph 1 - [temp.arg.template):

Show content from different parts or fields in Orchard template


Tag : development , By : user169463
Date : March 29 2020, 07:55 AM
With these it helps I'd opt for the second solution and create either an alternate for your title part or for the field and leave content as it is.
So if your content was called TestContent, you could create an alternate called
Parts.Title-TestContent.cshtml
var url = Url.ItemDisplayUrl((Orchard.ContentManagement.IContent) Model.ContentItem.TestContent.MyContentPicker.ContentItems[0]);

Can a template template parameter default reference other template type parameters?


Tag : cpp , By : Rit Li
Date : March 29 2020, 07:55 AM
will be helpful for those in need Depending on your definition of "similar", you could change your B template definition into
template <typename V, typename W = A<V>>
struct B
{
};
W::template AA< some_type >

default const char* template argument in a template template function


Tag : cpp , By : m0gb0y74
Date : March 29 2020, 07:55 AM
around this issue It seems to me you want to combine two separate things in one: default type and default variable value of that type. But that's impossible and it seems pretty reasonable to me.
Slightly flexible approach will do what you asked for:
template <template <typename, typename > class Container, class Element, class Allocator, class Sep = const char*>
void displayContentsWithDefaultTemplateArgs(const Container<Element, Allocator>& inputContainer, Sep sep = ",")
{
    copy(inputContainer.cbegin(), inputContainer.cend(), ostream_iterator<Element>(cout, sep));
    cout << endl;
};

Template variables with template argument deduction and default template parameters


Tag : cpp , By : HokieGeek
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Disclaimer: the following is valid in context of C++14. With C++17 both compilers are wrong. See the another answer by Barry.
Looking into details I see that Clang is correct here, while GCC is confused.
template <typename T, typename U = int> int variable = 0;
template <typename T = int, typename U> extern int variable;

int main()
{
    // accepted by clang++-3.9 -std=c++14
    std::cout << variable<> << '\n';
    return 0;
}
template <typename T, typename U = int> using alias = int;
template <typename T = int, typename U> using alias = int;

int main()
{
    alias<> v = 0;
    std::cout << v << '\n';
    std::cout << typeid(v).name() << '\n';
    return 0;
}
$ ./a.out | c++filt -t
0
int
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