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Python: split string by closing bracket and write in new line


Python: split string by closing bracket and write in new line

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Python: split string by closing bracket and write in new line
Tag : python , By : Alex Sadzawka
Date : November 24 2020, 09:00 AM

it fixes the issue You don't need a regex just str.replace any closing paren with a closing paren followed by a newline:
s="This is one sentence()This is another sentence()This is a full sentence at all)Maybe this too)This is the last sentence()"

print(s.replace(")",")\n"))
This is one sentence()
This is another sentence()
This is a full sentence at all)
Maybe this too)
This is the last sentence()

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How to automatically move opening bracket on a new line and add closing curly bracket in Visual Studio 2015?


Tag : chash , By : alexmajy
Date : March 29 2020, 07:55 AM
this one helps. You can try ReSharper(30 days free trial) or Code maid extension which is really good at reorganizing code (http://www.codemaid.net/)
This may also help

Configuring phpcs to disallow spaces after closing bracket and before closing bracket


Tag : wordpress , By : warttack
Date : March 29 2020, 07:55 AM
seems to work fine You don't actually want to exclude those 2 PEAR rules. You'll want to override the setting that the WordPress standard uses instead, changing it from 1 required space to 0 required spaces.
The WordPress Core ruleset.xml file includes this section:
<rule ref="PEAR.Functions.FunctionCallSignature">
    <properties>
        <property name="requiredSpacesAfterOpen" value="1"/>
        <property name="requiredSpacesBeforeClose" value="1"/>
    </properties>
</rule>
<rule ref="PEAR.Functions.FunctionCallSignature">
    <properties>
        <property name="requiredSpacesAfterOpen" value="0"/>
        <property name="requiredSpacesBeforeClose" value="0"/>
    </properties>
</rule>

error Expected 1 line break before closing bracket, but no line breaks\ found vue/html-closing-bracket-newline


Tag : javascript , By : Ted Leung
Date : March 29 2020, 07:55 AM
To fix the issue you can do As per documentation
"multiline": "never"

How can I remove a line from java source code(from file) that has only a opening or closing bracket in python?


Tag : python , By : RichAA
Date : March 29 2020, 07:55 AM
Does that help Use splitlines() to split the text file to rows and use startswith() to check if a string starts with a substring.
with open("source_code.txt", 'r') as f:
    rows = f.read().splitlines()

output = []

for row in rows:
    if not (row.lstrip().startswith("{") or row.lstrip().startswith("}")):
        output.append(row)

with open("source_code.txt", 'w') as f:
    for row in output:
        f.write(row + '\n')
/**
     * Copy all mappings from given map if they pass validation.
     * If a single value fails validation, none of the others will be committed either.
     *
     * @param map map of keys and values
     * @throws ValidationException if an entry in <tt>map</tt> fails validation
     */
    public void putAll(Map<K, V> map)
    throws ValidationException
        for (K key: map.keySet()) {
            if (mValidators.containsKey(key)) {
                for (Validator validator : mValidators.get(key)) {
                    if (!validator.validate(map.get(key))) {      
                       throw new ValidationException(validator.message());

        mData.putAll(map);

Bracket Matching - Find closing bracket with input bracket index - ValueError


Tag : python , By : S Hall
Date : March 29 2020, 07:55 AM
may help you . This is kind of an odd way to do this (I would usually do things like this with a stack). But I can see a few issues, including the one that causes the value error.
The first is that string[b+c:] replaces everything from index b+c onward, you really wanted string[b+c]. So on the first run "(([()]))" becomes "(([..", which is not what you want.
def matching_bracket(string, idx):
    a = {
        "(": ")",
        "[": "]",
        "{": "}",
        "<": ">"
    }
    close_bracket = a[string[idx]]

    if idx != string.rindex(string[idx]):      #if open bracket is first bracket
        b = string.rindex(string[idx])         #rightmost open bracket
        c = string[b:].index(close_bracket)             #next closest close bracket
        str_list = list(string)
        str_list[b], str_list[b+c] = ".", "."              #replace both
        return matching_bracket(''.join(str_list), idx)  # recurse
    else:
        d = string[idx:].index(close_bracket)
        return idx + d
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