With D3, how can I avoid SVG graph links being rendered over nodes?

With D3, how can I avoid SVG graph links being rendered over nodes?

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hop of those help? Create two SVG groups () to act as layers, and keep your nodes and links in different layers.
Here's the gist of it:
var vis = d3.select("body").append("svg"); // Visualisation root

// Append layers in desired draw order; these groups are permanent elements.
var linksLayer = vis.append("g").attr("id", "links-layer");
var nodesLayer = vis.append("g").attr("id", "nodes-layer");


// Inside the layer-groups, shuffle nodes around as needed based on data.

var nodes = nodesLayer.selectAll(".node").data(nodeData);
nodes.enter() ...

var links = linksLayer.selectAll(".link").data(linkData);
links.enter() ...

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Tag : javascript , By : wiznick
Date : March 29 2020, 07:55 AM
help you fix your problem If you always PREpend any link (i.e. add the links to the container before any of the nodes), there will never be a link overlapping a node. You do that with insert(), which will prepend as long as you specify a selector matching the nodes you want to keep in on top:
  .attr('class', 'node')

  .insert('div', '.node') // Inserts link before any of the existing nodes

Asynchronous update of nodes properties after the graph is rendered (Vivagraph.js)

Tag : development , By : UpperLuck
Date : March 29 2020, 07:55 AM
will help you As I said in the comments, any work you want to do as a result of an asynchronous process must be done in the callback. This includes any rendering work.
For jQuery's deferreds (like the result of an Ajax call), the callback is defined through .then or .done, enabling you to detach the act of fetching a resource from working with that resource.
function fetchInfo(id) {
    var root = 'http://jsonplaceholder.typicode.com';
    return $.getJSON(root + '/photos/' + id);

function main() {
    var graph = Viva.Graph.graph(),
        graphics = Viva.Graph.View.svgGraphics(),
        nodeSize = 24,
        addRelatedNodes = function (nodeId, count) {
            var childId, i;
            for (i = 0; i < count; ++i) {
                childId = Math.floor(Math.random() * 150) + nodeId;
                graph.addLink(nodeId, childId);
        .node(function (node) {
            var ui = Viva.Graph.svg('image')
                .attr('width', nodeSize)
                .attr('height', nodeSize)
            $(ui).dblclick(function () {
                addRelatedNodes(node.id, 6);

            // render when ready
            fetchInfo(node.id).done(function (data) {

            return ui;
        .placeNode(function (nodeUI, pos) {
            nodeUI.attr('x', pos.x - nodeSize / 2).attr('y', pos.y - nodeSize / 2);
        .link(function (link) {
            return Viva.Graph.svg('path')
                .attr('stroke', 'gray');
        .placeLink(function (linkUI, fromPos, toPos) {
            var data = 
                'M' + fromPos.x + ',' + fromPos.y +
                'L' + toPos.x + ',' + toPos.y;

            linkUI.attr("d", data);

    graph.addLink(1, 2);

    Viva.Graph.View.renderer(graph, {
        graphics: graphics

svg {
    width: 100%;
    height: 100%;
img {
    cursor: pointer;
<script src="https://rawgit.com/anvaka/VivaGraphJS/master/dist/vivagraph.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

Is there a graph algorithm to find shortest path between nodes, incorporating nodes to avoid?

Tag : algorithm , By : Matt Watson
Date : March 29 2020, 07:55 AM
Hope that helps Temporarily eliminate the nodes you must avoid and those near them or change the weights of the appropriate edges to infinity. Then use any standard path-finding algorithm.

Tag : javascript , By : Shrek Qian
Date : March 29 2020, 07:55 AM
To fix the issue you can do It looks like you are trying to create a nodes object by iterating over your links array, but you have your nodes variable set to an empty array. Instead, you should set it as an empty object: nodes = {}. It would make more sense to wrap links.forEach() in a function since it seems like the idea would be to call it multiple times and either return the nodes object value (if it has been created), or create it if it does not yet exist. Try the example (logging added so you can see the result of the code):
const links = [
  {source: "A", target: "B"},
  {source: "B", target: "C"},
  {source: "D", target: "E"},
  {source: "E", target: "C"}
const nodes = {};  
links.forEach((link) => {
  link.source = nodes[link.source] || (nodes[link.source] = {
    eid: link.source
  link.target = nodes[link.target] || (nodes[link.target] = {
    eid: link.target

Get the coordinates of the nodes of a rendered graph in Sigma.js

Tag : development , By : xie renhui
Date : March 29 2020, 07:55 AM
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