Partial string matching in javascript

Partial string matching in javascript

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Partial string matching in javascript
Tag : javascript , By : Funkwarrior
Date : November 24 2020, 09:00 AM

I think the issue was by ths following , I have this javascript function: , You will have to loop through the Array:
var arr = ['ab', 'f', 'c']

function find(a, c) {
  for(var i = 0; i < a.length; ++i) {
    if(a[i].indexOf(c) != -1)
      return i
  return -1

// Example:
document.body.innerHTML = find(arr, "b")

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Having String returned from String.split include partial of matching elements

Tag : java , By : alexandruz
Date : March 29 2020, 07:55 AM
Hope this helps Using Regex
While I must agree that using a JSON parser makes a lot more sense, even if you want to use regex, String.split() is not the right tool. Use a Pattern and a Matcher:
final String json = "\"name\" : \"john\" , \"worth\" : \"123,456\"";
final Pattern pattern =
    Pattern.compile("\"(.*?)\"\\s*:\\s*\"(.*?)\"", Pattern.DOTALL);
final Matcher matcher = pattern.matcher(json);
    System.out.println(matcher.group(1) + ":" + matcher.group(2));
final Pattern pattern =
    Pattern.compile("(\".*?\")\\s*:\\s*(\".*?\")", Pattern.DOTALL);
final String json = "{\"name\" : \"john\" , \"worth\" : \"123,456\"}";
final JSONObject jsonObject = new JSONObject(json);
final Iterator<String> it = jsonObject.keys();
    final String nextKey = it.next();
    System.out.println(nextKey + ":" + jsonObject.getString(nextKey));

Partial string matching in PHP

Tag : php , By : user167963
Date : March 29 2020, 07:55 AM
hop of those help? , Try this -
$var1 = 'accommodation_rate_fri_to_sun_garden_view';
$var2 = 'Garden View';
$var2 = str_replace(" ", "_", strtolower($var2));
if (  stripos($var1, $var2) !== false ) {
    echo 'found';
else {
    echo 'not found';

Partial string matching in R

Tag : r , By : Steve Jones
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am trying to remove 'bad' email addresses from a csv. I have a column of emails that look like "abd@no.com," "123@none.com," "@," or "a". There is a wide range of email formats so I want to try to find and remove them all. , Your function is pretty close. Just note a few tweaks:
email_clean <- function(email, invalid = NA)
        email <- trimws(email)               # remove whitespace
        email[nchar(email) %in% c(1,2)] <- invalid
        bad_email <- c("\\@no.com", "\\@none.com","\\@email.com","\\@noemail.com")
        pattern = paste0("(?i)\\b",paste0(bad_email,collapse="\\b|\\b"),"\\b")
        email <-gsub(pattern, invalid, sapply(email,as.character))

emails <- c("pierre@gmail.com", "hi@none.com", "@", "a")
# [1] "pierre@gmail.com" NA                 NA                
# [4] NA  

Partial String Matching by Row

Tag : r , By : boney M
Date : March 29 2020, 07:55 AM
wish helps you I'm trying to create a unique column in a data frame that has a numeric of the character matches between two strings from the left side of both strings. , This code works for your example:
df$z <- mapply(function(x, y) which.max(x != y),
               strsplit(as.character(df$x), split=""),
               strsplit(as.character(df$y), split="")) - 1

       x    y z
1    yhf   yh 2
2 rnmqjk rnmj 3
3    wok   ok 0
df$z[as.character(df$x) == as.character(df$y)] <-
                        nchar(as.character(df$x[as.character(df$x) == as.character(df$y)]))

Filtering object based on partial string matching in JavaScript

Tag : javascript , By : brennen
Date : March 29 2020, 07:55 AM
it fixes the issue Array.filter is your friend here. Alongside that, .includes is also your friend:
Array.filter Array.includes
const baseHeroes = [
  { name: "Batman", powers: ["Strength", "Intelligence"] },
  { name: "Superman", powers: ["Strength", "Flying"] },
  { name: "Spiderman", powers: ["Spider Sense", "Webs"] },
  { name: "The Flash", powers: ["Speed"] },
  { name: "Captain America", powers: ["Strength", "Shield"] },

const results = baseHeroes.filter( h => h.powers.includes('Strength') );

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