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Python - CSV Reading with dictionary


Python - CSV Reading with dictionary

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Python - CSV Reading with dictionary
Tag : python , By : alexandruz
Date : November 23 2020, 09:01 AM

wish of those help So, , Try this:
choice = random.choice(list(capital_of.keys()))

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populate SQL table by reading tweets from dictionary within a dictionary using Python


Tag : python , By : deanschang
Date : March 29 2020, 07:55 AM
around this issue Your code is failing for a few reasons. Since this appears to be an assignment, I will not post the working code here, but I will attempt to point you in the right direction. Here are some of the things I've noticed while testing your code:
You made the assumption that tweet['geo'] would be an empty string. It actually is not. Essentially, the data sets this value to a json "null" when no geo information is available; this gets translated to the Nonetype in python, and not an empty string. Therefore, you should not be checking for the length of that value, but rather whether that value is True (hint: python considers '', "", [], ,{}, None as False) I don't think your indentation on lines 28-31 is correct. Shouldn't that logic execute in the if block? right now, you are always executing that code, which I think is a logical error. In your exception trapping at line 31, where do you define the variable "i"?

creating dictionary within a dictionary in python reading some data is a csv file


Tag : python , By : Mariocki
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have a csv file called sample.csv which contains the following data:- , A solution with csv module
import dateutil.parser
import csv

data_dict = {}
with open('data.csv', 'r') as csvfile:
    csvreader = csv.reader(csvfile)
    for row in csvreader:
        dt = dateutil.parser.parse(row[0])
        if not data_dict.get(dt.hour,''):
            data_dict[dt.hour] = {}
        if not data_dict[dt.hour].get(dt.minute,''):
            data_dict[dt.hour][dt.minute]=[]
        data_dict[dt.hour][dt.minute].append(row[1:])

Python: Reading in .csv data as dictionary and printing out data as dictionary to .csv file?


Tag : python-2.7 , By : T11M
Date : March 29 2020, 07:55 AM
Hope that helps You're unfortunately tricked by your own testing, that is, the printing of the individual rows. By looping through csv_file initially, you've exhausted the iterator and are at the end. Further iterations, as done in the bottom of your code, are not possible and will be ignored.
Your question is essentially a duplicate of various other question, such as how to read from a CSV file repeatedly. Albeit that the issue here comes up in a different way: you didn't realise what the problem was, while those questions do know the cause, but not the solution.
infile = open(sys.argv[1], 'rU')
csv_file = csv.DictReader(infile ,delimiter = ',')

<all other code>

infile.seek(0)
for row in csv_file:
    csvwriter.writerow(row)
test_file.close()
infile.close()
with open(sys.argv[1], 'rU') as infile, open('test2.csv', 'wr') as outfile:
    csv_file = csv.DictReader(infile ,delimiter = ',')
    for line in csv_file:
        print line['Name'] + ',' + line['DOB']
    fieldnames = ['Name','DOB']
    csvwriter = csv.DictWriter(outfile, delimiter=',', fieldnames=fieldnames)
    infile.seek(0)
    for row in csv_file:
        csvwriter.writerow(row)

Reading dictionary from file in Python


Tag : python , By : Guyou
Date : March 29 2020, 07:55 AM
I hope this helps you . I have a huge base of lockers assigned to people in a file with this structure: , Just do:
result = {}
with open('thefile.txt') as my_file:
    for line in my_file:
        name, locker_number = line.replace("'", "").split(':')
        result[name] = locker_number
print(result)
result = {}
with open('thefile.txt') as my_file:
    for line in my_file:
        name, locker_number = line.replace("'", "").split(':')
        if not name in result:
            result[name] = [locker_number]
        else:
            result[name].append(locker_number)

print(result)

for name in result:
    result[name] = ', '.join(result[name])  # will return a string of comma separated lockers.

print(result)

Reading from a file to a python dictionary


Tag : python , By : LinnheCreative
Date : March 29 2020, 07:55 AM
To fix the issue you can do This does not work because there are more than two values in the line:
(key, val) = line.split(',')
details[int(key)] = val
key, *values = line.split(',')
details[int(key)] = values
key, title, author, year, something = line.split(',')
details[int(key)] = title, author, year, something
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