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How to stop my character from going outside the div?


How to stop my character from going outside the div?

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How to stop my character from going outside the div?
Tag : javascript , By : Big Ant
Date : November 23 2020, 09:01 AM

around this issue I think all you need to do is check the bounds in your keydown handler:
$(document).keydown(function(e) {

var position = $('#charlie').position(),
    width = $('#charlie').width(),
    max = $('.container').width(),
    step = 20;

switch(e.keyCode) {

    case 39: // right
    if ( position.left + width + step < max ) {
        $('#charlie').css('left', position.left + step + 'px').removeClass('flip');
    }
    break;

    case 37: // left
    if ( position.left - step > 0 ) {
        $('#charlie').css('left', position.left - step + 'px').addClass('flip');
    }

}


});

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Get regex to stop at a certain character, but include that character in match


Tag : php , By : Juan Pablo
Date : March 29 2020, 07:55 AM
it fixes the issue Right now, this regex matches something and stops at a slash ( / ), but I need it to stop at the slash and include the slash. Or in other words stop at whatever character is after the slash. But, I don't know what that charcter is. , You can do it in 2 ways :
(?:https?:\/\/|www)[^\/]*\/
(?:https?:\/\/|www).*?\/
(?:https?:\/\/|www)[^\/]+(?:\S*?\/)*

Is there a way to stop a RegEx before a character value and start another one after that character?


Tag : java , By : mediafarm
Date : March 29 2020, 07:55 AM
wish of those help I'll first suggest two alternate approaches, then answer your question as it stands.
Perhaps beter without regular expressions
// Multiplication of unparenthesized integers
Pattern p = Pattern.compile("(\\d+)\\s*\\*\\s*(\\d+)");
Matcher m = p.matcher(s);
while (m.find()) {
  int a = Integer.parseInt(m.group(1));
  int b = Integer.parseInt(m.group(2));
  s = s.substring(0, m.start(1)) + (a*b) + s.substring(m.end(2));
  m.reset(s);
}

Using scanf for character input, but the do-while loop wont stop at the null character


Tag : c , By : Hans-Inge
Date : March 29 2020, 07:55 AM
this one helps. There aren't any nul-terminated strings here, but only string arrays.
So, when pressing enter, a[i-1] is \n not \0 (scanf with %c as parameter doesn't nul-terminate the strings, and ENTER is just a non-nul character with code 10 AKA \n)
#include <stdio.h>
main()
{
      char a[50];
      int i;

      printf("Give max 50 characters\n");

      i=0;

      do
      {
            scanf("%c", &a[i]);
            i=i+1;
      }
      while((i<sizeof(a)) && (a[i-1]!='\n'));  // \n not \0
      int j;
      for(j=0; j<i; j++)  // stop at i
            printf("%c", a[j]);  // output is flushed when \n is printed
 }

PHP Remove Everything After Character and Stop Before Character


Tag : php , By : Patastroph
Date : March 29 2020, 07:55 AM
this will help Should be able to use PHP's strstr in-built function in combination with str_replace to get the result you're after
$string = '/my-picture-gallery-1000x2000.jpg';
echo str_replace(strrchr($string, '-'), '', $string) . strstr($string, '.');
$string = '/my-picture-gallery-1000x2000.jpg';

$dimensions = strrchr($string, '-');
$extension = strrchr($string, '.');

$image = str_replace($dimensions, '', $string) . $extension;

How can I capitalize every letter after the > character and stop it when the < character is met?


Tag : javascript , By : adbanginwar
Date : March 29 2020, 07:55 AM
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