Finding out the duplicate element in an array
Tag : c , By : user169463
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , There are many ways that you can think about this problem, depending on the constraints of your problem description. If you know for a fact that exactly one element is duplicated, then there are many ways to solve this problem. One particularly clever solution is to use the bitwise XOR operator. XOR has the following interesting properties:
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Finding duplicate values in dictionary and print Key of the duplicate element
Date : March 29 2020, 07:55 AM
around this issue It depends. If you have an ever changing dictionary and need to get that information only once, use this: MyDict.GroupBy(x => x.Value).Where(x => x.Count() > 1)
var lookup = MyDict.ToLookup(x => x.Value, x => x.Key).Where(x => x.Count() > 1);
foreach(var item in lookup)
{
var keys = item.Aggregate("", (s, v) => s+", "+v);
var message = "The following keys have the value " + item.Key + ":" + keys;
Console.WriteLine(message);
}
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Finding any duplicate element in array
Tag : java , By : Shawazi
Date : March 29 2020, 07:55 AM
Hope this helps I think what's happening is that you are not being prompted to enter a number with a System.out.println("Enter a number: "); So you think the program is not working, when really it is just waiting for you to keep entering numbers. You may want to prompt with System.out.println()s on each iteration: System.out.println("Input elements in array" +size);
for(int j = 0;j<size;j++){
System.out.println("Enter a number: ");
a[j] = sc.nextInt();
}
int[] a;
int[] b;
Scanner sc = new Scanner(System.in);
System.out.println("Enter size of array");
int size = sc.nextInt();
a = new int[size];
b = new int[size];
System.out.println("a[] " + Arrays.asList(a));
for(int j = 0;j<size;j++){
System.out.println("Enter a number: ");
a[j] = sc.nextInt();
b[j] = a[i];
}
int dupCount = 0;
for (int i = 0; i < size; i++){
for (int j = 0; j < size; j++){
if (b[i] == a[j]){
Duplicate = a[j];
System.out.println(Duplicate);
dupCount = 0;
}
}
}
if (dupCount == 0)
System.out.println("No common variable");
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Finding the duplicate element in a (sorted) Array in less than O(n) time?
Date : March 29 2020, 07:55 AM
With these it helps Binary search only works if you know the element you're looking for (or, more exactly, if you can tell which half it's in when you've chosen your pivot point). There is nothing in your question that seems to indicate you have this knowledge so, based on that, O(n) is the best you can currently do.
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Finding duplicate element in an array?
Tag : java , By : greggerz
Date : March 29 2020, 07:55 AM
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