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Finding non duplicate element in an array


Finding non duplicate element in an array

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Finding non duplicate element in an array
Tag : java , By : user126922
Date : November 24 2020, 01:01 AM

fixed the issue. Will look into that further Since this is almost certainly a learning exercise, and because you are very close to completing it right, here are the things that you need to change to make it work:
Move the declaration of flag inside the outer loop - the flag needs to be set to true every iteration of the outer loop, and it is not used anywhere outside the outer loop. Check the flag when the inner loop completes - if the flag remains true, you have found a unique number; return it.

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Finding out the duplicate element in an array


Tag : c , By : user169463
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , There are many ways that you can think about this problem, depending on the constraints of your problem description.
If you know for a fact that exactly one element is duplicated, then there are many ways to solve this problem. One particularly clever solution is to use the bitwise XOR operator. XOR has the following interesting properties:

Finding duplicate values in dictionary and print Key of the duplicate element


Tag : chash , By : jaset
Date : March 29 2020, 07:55 AM
around this issue It depends. If you have an ever changing dictionary and need to get that information only once, use this:
MyDict.GroupBy(x => x.Value).Where(x => x.Count() > 1)
var lookup = MyDict.ToLookup(x => x.Value, x => x.Key).Where(x => x.Count() > 1);
foreach(var item in lookup)
{
    var keys = item.Aggregate("", (s, v) => s+", "+v);
    var message = "The following keys have the value " + item.Key + ":" + keys;
    Console.WriteLine(message);
}

Finding any duplicate element in array


Tag : java , By : Shawazi
Date : March 29 2020, 07:55 AM
Hope this helps I think what's happening is that you are not being prompted to enter a number with a System.out.println("Enter a number: "); So you think the program is not working, when really it is just waiting for you to keep entering numbers. You may want to prompt with System.out.println()s on each iteration:
System.out.println("Input elements in array" +size);
for(int j = 0;j<size;j++){
    System.out.println("Enter a number: ");
    a[j] = sc.nextInt();
}
int[] a; 
int[] b;

Scanner sc = new Scanner(System.in);
System.out.println("Enter size of array");
int size = sc.nextInt();

a = new int[size];
b = new int[size];
System.out.println("a[] " + Arrays.asList(a));
for(int j = 0;j<size;j++){
    System.out.println("Enter a number: ");
    a[j] = sc.nextInt();
    b[j] = a[i];
}
int dupCount = 0;
for (int i = 0; i < size; i++){
    for (int j = 0; j < size; j++){
        if (b[i] == a[j]){
            Duplicate = a[j];
            System.out.println(Duplicate);
            dupCount = 0;
        }
    }
}
if (dupCount == 0)
    System.out.println("No common variable");

Finding the duplicate element in a (sorted) Array in less than O(n) time?


Tag : javascript , By : Adrian Codrington
Date : March 29 2020, 07:55 AM
With these it helps Binary search only works if you know the element you're looking for (or, more exactly, if you can tell which half it's in when you've chosen your pivot point).
There is nothing in your question that seems to indicate you have this knowledge so, based on that, O(n) is the best you can currently do.

Finding duplicate element in an array?


Tag : java , By : greggerz
Date : March 29 2020, 07:55 AM
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