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Add Elements to nullable Vector


Add Elements to nullable Vector

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Add Elements to nullable Vector
Tag : arrays , By : Mahyar Sepehr
Date : November 24 2020, 01:01 AM

I wish this helpful for you The easiest way would be to not use a nullable Vector. private Vector $lines = Vector {}; gets around the need for a constructor too.
Otherwise, you'll need to check if the value isn't null, then append to it:
public function addLine(string $line): void {
    $vec = $this->lines;
    if ($vec !== null) $vec[] = trim($line);
}

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Syntax (and/or functions) for applying an op over elements of one vector, using as arg elements of a 2nd vector


Tag : r , By : Mena
Date : March 29 2020, 07:55 AM
hope this fix your issue I am trying to find the right expression for creating a vector result by applying an operation over an vector, using, in a vectorised way, elements of a 2nd vector. The use case is that I have a vector of raw values, and a vector of breakpoints. What I want is an expression that will give me the result of applying a sum of a logical operation on the breakpoints with respect to the values in the values vector. In other words: , You can do it in three steps:
 as.data.frame(t(sapply(breaksfoo, 
                        function(x) list(breaks = x, nmatching = sum(x > rawfoo)))))
  breaks nmatching
1     10         2
2     50         5
3     80         6

Use references to some elements of a std::vector, or the position of such elements in the vector, to iterate over them


Tag : cpp , By : Fenix Drakken
Date : March 29 2020, 07:55 AM
Any of those help You can't store references in a container and in any case, even if the compiler/language allowed it, you will still need two dereferences to evaluate each iteration.
By the way, if C++11 is available, you could rewrite the loop as:
for(auto& elem : elements_i_like)
    elem.do_something();

loop to remove repeated elements of a vector and add corresponding elements of another vector


Tag : arrays , By : user152423
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I would prefer using built in functions, but assuming you have to stick to your own approach, you can try this:
a=[5,6,8,9,6,7,9,10,8,9,11,12];
b=[1,7,1,-1,3,21,3,-3,-4,-28,-4,4];

n = numel(a);
remove = zeros(1,n);

temp = a;
for ii = 1:n
    for jj = ii+1:n
        if temp(ii) == temp(jj)
            temp(ii) = NaN;
            remove(ii) = ii;
            b(jj) = b(jj) + b(ii);

        end
    end
end

a(remove(remove>0)) = []
b(remove(remove>0)) = []

a =
     5     6     7    10     8     9    11    12
b =
     1    10    21    -3    -3   -26    -4     4

How to replace specific elements of a vector with elements of a string vector?


Tag : string , By : haver
Date : March 29 2020, 07:55 AM
Any of those help As you have already shown a lot of effort I will try to clear some things up for you. The replacement of 1 to 5 with 65 to 70 is due to the ASCII table which represents all characters with integers. As you have an integer array MATLAB will convert the characters with its numerical ASCII value. You can invert this with char(65:70) = ABCDEF;
Also you can index the position of grades multiple times. char_grades =letters(grades) will do the trick. Or to do it in a convoluted way.
g = @(x) letters(x);
char_grades = g(grades);

Counting the number of elements in vector x which equal any vector element in vector y


Tag : r , By : Barry
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I need to count the number of elements in vector x which equal any vector element in vector y. , Try length-which-in:
length(which(x %in% y))
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