logo
down
shadow

Treat argument as string in Tcl 'expr' statement


Treat argument as string in Tcl 'expr' statement

Content Index :

Treat argument as string in Tcl 'expr' statement
Tag : if-statement , By : can
Date : November 24 2020, 01:01 AM

wish help you to fix your issue The expr language is rather different to the rest of Tcl. You have to care much more about syntax there. Putting things in "double quotes" can help.
set Register [expr {$Parameter eq "Unique" ? "ControlStatus" : $Parameter}]
set Data [expr {$Parameter eq "Unique" ? "${Value}0" : $Value}]
set Mask [expr {$Parameter eq "Unique" ? "EF" : {}}]
set Register [if {$Parameter eq "Unique"} {string cat ControlStatus} {string cat $Parameter}]
set Data [if {$Parameter eq "Unique"} {string cat $Value 0} {string cat $Value}]
set Mask [if {$Parameter eq "Unique"} {string cat EF}]
# We can omit the else clause; the default is an empty string anyway
set Register [if {$Parameter eq "Unique"} {return -level 0 ControlStatus} {return -level 0 $Parameter}]
set Data [if {$Parameter eq "Unique"} {return -level 0 ${Value}0} {return -level 0 $Value}]
set Mask [if {$Parameter eq "Unique"} {return -level 0 EF}]
proc value {value} {return $value}
set Register [if {$Parameter eq "Unique"} {value ControlStatus} {value $Parameter}]
set Data [if {$Parameter eq "Unique"} {value $Value 0} {value $Value}]
set Mask [if {$Parameter eq "Unique"} {value EF}]
set Register $Parameter
set Data $Value
set Mask ""
if {$Parameter eq "Unique"} {
    set Register ControlStatus
    append Data 0
    set Mask EF
}

Comments
No Comments Right Now !

Boards Message :
You Must Login Or Sign Up to Add Your Comments .

Share : facebook icon twitter icon

Force auto-increment to treat its argument as string


Tag : perl , By : gorbiz
Date : March 29 2020, 07:55 AM
will help you Here's the related question about how auto incrementing works: Autoincrementing letters in Perl
Like the docs explained, basically you need the variable to
#!/usr/bin/perl
use strict;
use warnings;


my $test = "1000";
for (0..100) {
    $test = increment($test);
}
print $test . "\n";

$test = "M2V3";
for (0..100) {
    $test = increment($test);
}
print $test . "\n";


sub increment {
    my ($str) = @_;

    my @letters = reverse split //, $str;

    my $add = "";
    my $increment = 1;
    my $result = "";


    for my $let (@letters) {
        if ( $increment == 1 ) {
            ++$let;
        }
        if ( $let =~ /(.)(.)/ ) {
            $add = $2;
            $increment = 1;
        } else {
            $add = $let;
            $increment = 0;
        }
        $result = $add . $result;
    }
    return $result;
}
1101
M3F4

Is it possible to make this YACC grammar unambiguous? expr: ... | expr expr


Tag : development , By : Gerhard Miller
Date : March 29 2020, 07:55 AM
it should still fix some issue The ambiguity results from the fact that you allow unary operators (- expr), so 2 - 2 can be parsed either as a simple subtraction (yielding 0) or as an implicit product (of 2 and -2, yielding -4).
It's clear that subtraction is intended (otherwise subtraction would be impossible to represent) so it is necessary to ban the production expr: expr expr if the second expr on the right-hand side is a unary operation.
term: NUM
    | '(' expr ')'
unop: term
    | '-' unop
    | '+' unop
conc: unop
    | conc term
prod: conc
    | prod '*' conc
    | prod '/' conc
expr: prod
    | expr '+' prod
    | expr '-' prod

How to make jq treat argument as numeric instead of string?


Tag : bash , By : Jesse
Date : March 29 2020, 07:55 AM
this one helps. You can convert it to a number, like this:
jq --arg ARG1 1 '.[$ARG1|tonumber]' <<< '["foo". "bar"]'
"bar"

Bison - treat expr according to syntax expectations


Tag : development , By : Marc Dong
Date : March 29 2020, 07:55 AM
will help you There are a couple of issues with that grammar.
There isn't really a problem with APPSOME1, which takes either expr or array, expr. As soon as the comma is seen, it is clear which option to choose (but see below about parentheses). However, APPSOME2 is not going to work:
APPSOME2: expr ',' expr
        | array ',' expr ',' expr
args_variable
    : APPVARIABLE
    | '(' args_variable ')'
expr: args_variable
    | '(' expr ')'
APPSOME1 (((ARRAYNAME))), expr
APPSOME1 expr
APPSOME1 array expr
APPSOME2 expr, expr
APPSOME2 array expr, expr

Treat input argument in Scala function as a String in ScalikeJDBC select query


Tag : scala , By : Chris Hanley
Date : March 29 2020, 07:55 AM
I hope this helps you . You can use SQLSyntax.createUnsafely to convert your string into SQLSyntax:
def selectDQTableAndSiteList(schemaName:String) (implicit s:DBSession = AutoSession) : List[String] = {
   val schema = SQLSyntax.createUnsafely(schemaName)
   sql"select CONCAT(name, ${"#"} , age) as tablename from ${schema}.employee where status = 'Y'".map(_.string("tablename")).list().apply()
}
Related Posts Related QUESTIONS :
shadow
Privacy Policy - Terms - Contact Us © scrbit.com