Force auto-increment to treat its argument as string
Date : March 29 2020, 07:55 AM
will help you Here's the related question about how auto incrementing works: Autoincrementing letters in PerlLike the docs explained, basically you need the variable to #!/usr/bin/perl
use strict;
use warnings;
my $test = "1000";
for (0..100) {
$test = increment($test);
}
print $test . "\n";
$test = "M2V3";
for (0..100) {
$test = increment($test);
}
print $test . "\n";
sub increment {
my ($str) = @_;
my @letters = reverse split //, $str;
my $add = "";
my $increment = 1;
my $result = "";
for my $let (@letters) {
if ( $increment == 1 ) {
++$let;
}
if ( $let =~ /(.)(.)/ ) {
$add = $2;
$increment = 1;
} else {
$add = $let;
$increment = 0;
}
$result = $add . $result;
}
return $result;
}
1101
M3F4
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Is it possible to make this YACC grammar unambiguous? expr: ... | expr expr
Date : March 29 2020, 07:55 AM
it should still fix some issue The ambiguity results from the fact that you allow unary operators (- expr), so 2 - 2 can be parsed either as a simple subtraction (yielding 0) or as an implicit product (of 2 and -2, yielding -4). It's clear that subtraction is intended (otherwise subtraction would be impossible to represent) so it is necessary to ban the production expr: expr expr if the second expr on the right-hand side is a unary operation. term: NUM
| '(' expr ')'
unop: term
| '-' unop
| '+' unop
conc: unop
| conc term
prod: conc
| prod '*' conc
| prod '/' conc
expr: prod
| expr '+' prod
| expr '-' prod
|
How to make jq treat argument as numeric instead of string?
Date : March 29 2020, 07:55 AM
this one helps. You can convert it to a number, like this: jq --arg ARG1 1 '.[$ARG1|tonumber]' <<< '["foo". "bar"]'
"bar"
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Bison - treat expr according to syntax expectations
Date : March 29 2020, 07:55 AM
will help you There are a couple of issues with that grammar. There isn't really a problem with APPSOME1, which takes either expr or array, expr. As soon as the comma is seen, it is clear which option to choose (but see below about parentheses). However, APPSOME2 is not going to work: APPSOME2: expr ',' expr
| array ',' expr ',' expr
args_variable
: APPVARIABLE
| '(' args_variable ')'
expr: args_variable
| '(' expr ')'
APPSOME1 (((ARRAYNAME))), expr
APPSOME1 expr
APPSOME1 array expr
APPSOME2 expr, expr
APPSOME2 array expr, expr
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Treat input argument in Scala function as a String in ScalikeJDBC select query
Tag : scala , By : Chris Hanley
Date : March 29 2020, 07:55 AM
I hope this helps you . You can use SQLSyntax.createUnsafely to convert your string into SQLSyntax: def selectDQTableAndSiteList(schemaName:String) (implicit s:DBSession = AutoSession) : List[String] = {
val schema = SQLSyntax.createUnsafely(schemaName)
sql"select CONCAT(name, ${"#"} , age) as tablename from ${schema}.employee where status = 'Y'".map(_.string("tablename")).list().apply()
}
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