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how to print dynamic variable value in php


how to print dynamic variable value in php

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how to print dynamic variable value in php
Tag : php , By : Ashaea
Date : November 23 2020, 01:01 AM

may help you . how to get value or same name variable but end with different index , You can try like
echo '--'.${"item" . $i};
$item[1]='100';
$item[2]='200';
$item[3]='300';
$item[4]='400';
$item[5]='500';

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Tag : development , By : user118656
Date : March 29 2020, 07:55 AM
it fixes the issue The crucial behaviour is described under the More Information section of the documentation for DynamicModule:
a = {1, 2, 3};

DynamicModule[{b},
 Print[Dynamic[b]];
 {Dynamic[a], Dynamic[b]}
 ,
 Initialization :> (b = Length[a]; Print["init:", b]; a = a + 2)
 ]
        b$107

Out[7]= {{3, 4, 5}, 3}

        init:3
Print[Dynamic[b$107]]; {Dynamic[a], Dynamic[b$107]}
Cell[BoxData[
 DynamicModuleBox[{$CellContext`b$$ = 3}, 
  RowBox[{"{", 
   RowBox[{
    DynamicBox[ToBoxes[$CellContext`a, StandardForm],
     ImageSizeCache->{57., {2., 8.}}], ",", 
    DynamicBox[ToBoxes[$CellContext`b$$, StandardForm],
     ImageSizeCache->{7., {0., 8.}}]}], "}"}],
  DynamicModuleValues:>{},
  Initialization:>($CellContext`b$$ = 
    Length[$CellContext`a]; $CellContext`a = $CellContext`a + 2)]], "Output"]

Tag : python , By : Hunter
Date : March 29 2020, 07:55 AM
With these it helps I have a list of string with variable length. I do know that the minimum length of the list is 4. How do I print the list in the following format if the list grows to more than 4? , I would first transform the list as required and then use str.join():
>>> print (" ".join([strlist[2]] + [strlist[0]] + strlist[4:]))
c a f g h i j

What is the difference between print('text' +str(variable)) and print('stuff', variable) in python?


Tag : python , By : Cadu
Date : March 29 2020, 07:55 AM
Hope this helps your main difference is if you were to "parameterize" the print function (as Vikram so eloquently said), print has a default sep parameter that separates your parameters with whatever sep may be (defaulted to a ' '). without splitting your variables into parameters and just concatenating them into one string, there will be no spaces. ie:
>>> print(1,2)
1 2
>>> print(str(1)+str(2))
12
sep.join(parameters) #where sep is defaulted to ' '

Tag : java , By : SA.
Date : October 24 2020, 01:32 PM
will help you If I understood you correctly, you are not trying to increase the size of the array, what you are trying to do is increase a counter that iterates through the array and assigns the result of the d = a * b + c; equation to the ith element of the array. Then after all the elements in the array have been populated, you want to iterate through the array an print all the values. If that is the case you can modify your code as follows:
public class PrimeNumberCounter {

    public static void main(String[] args) {
        // Define integers
        int a = 1;
        final int b = 2;
        final int c = 3;
        //int d = 0; // not used
        // Define Array assuming that its size is fixed to 100
        int[] nth = new int[100];
        // Set the assignment loop
        for (a = 1; a <= nth.length; ++a) {
            // array indexing starts at 0
            nth[a - 1] = a * b + c;
        }
        // print loop
        for (int i = 0; i < nth.length; ++i) {
            System.out.printf("%d: %d\n", i + 1, nth[i]);
        }
    }
}
import java.util.List;
import java.util.ArrayList;

public class PrimeNumberCounter {

    public static void main(String[] args) {
        // Define integers
        int a = 1;
        final int b = 2;
        final int c = 3;
        // Some size N let's assume it's a 100 again
        List<Integer> nth = new ArrayList<Integer>();
        // Set the assignment loop
        for (a = 1; a <= 100; ++a) {
            // array indexing starts at 0
            nth.add(a - 1, a * b + c);
        }
        // print loop
        for (int i = 0; i < nth.size(); ++i) {
            System.out.printf("%d: %d\n", i + 1, nth.get[i]);
        }
    }
}

bash: print a dynamic variable using dynamic name


Tag : bash , By : Eniac
Date : March 29 2020, 07:55 AM
Any of those help You need to create a separate variable that will hold composite variable name:
# ccomposte variable name
var=CLIENTS_"${GEOZONE[$COUNT]}"

# assign value
declare $var="client1 client2"

# print it
echo "${!var}"
client1 client2
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