C RUBY-ON-RAILS MYSQL ASP.NET DEVELOPMENT RUBY .NET LINUX SQL-SERVER REGEX WINDOWS ALGORITHM ECLIPSE VISUAL-STUDIO STRING SVN PERFORMANCE APACHE-FLEX UNIT-TESTING SECURITY LINQ UNIX MATH EMAIL OOP LANGUAGE-AGNOSTIC VB6 MSBUILD

How to modify highstock chart so that it can be used for displaying ranks (Lowest values on highest points)

How to modify highstock chart so that it can be used for displaying ranks (Lowest values on highest points) Tag : highcharts , By : user133834 Date : November 23 2020, 01:01 AM

I hope this helps . To make the values go from lowest to highest you can use yAxis.reversed, like this:
``````yAxis: {
reversed: true
}
``````
``````data: [[1418860800000,1],[1419206400000,2],[1419292800000,3],[1419379200000,1],[1419465600000,1],[1419638400000,5],[1419724800000,7]]
``````
``````plotOptions: {
area: {
threshold: 7
}
}
``````

Share :

How to efficiently get highest & lowest values from a List<double?>, and then modify them?

Tag : chash , By : Der Ketzer
Date : March 29 2020, 07:55 AM
may help you . I have to get the sum of a list of doubles. If the sum is > 100, I have to decrement from the highest number until it's = 100. If the sum is < 100, I have to increment the lowest number until it's = 100. I can do this by looping though the list, assigning the values to placeholder variables and testing which is higher or lower but I'm wondering if any gurus out there could suggest a super cool & efficient way to do this? The code below basically outlines what I'm trying to achieve: , I'd do it something like this:
``````var splitValues = new List<double?>();

var listSum = splitValues.Sum(split => split.Value);
while (listSum != 100)
{
var value = listSum > 100 ? splitValues.Max() : splitValues.Min();
var idx = splitValues.IndexOf(value);
splitValues.RemoveAt(idx);
splitValues.Insert(idx, value + (listSum > 100 ? -1 : 1));
listSum = splitValues.Sum(split => split.Value);
}
``````

How to get the highest and the lowest points in the hash?

Tag : ruby , By : Barry
Date : March 29 2020, 07:55 AM
around this issue If you use Enumerable#max_by() or Enumerable#min_by() you can do following;
``````data = {
"1"  => {nick: "U1", points: 3},
"30" => {nick: "U30", points: 5},
"20" => {nick: "U20", points: 3}
}

max_id, max_data = data.max_by {|k,v| v[:points]}

puts max_id # => 30
puts max_data # => {nick: "U30", points: 5}
``````
``````minimal = Hash[*data.min_by {|k,v| v[:points]}]
puts minimal # => {"1"=>{:nick=>"U1", :points=>3}}
``````
``````min_id, min_data = data.min_by {|k,v| v[:points]}
all_minimal = data.select {|k,v| v[:points] == min_data[:points]}

puts all_minimal
# => {"1"=>{:nick=>"U1", :points=>3}, "20"=>{:nick=>"U20", :points=>3}}
``````

Sorting stacked bar chart based on the values ( highest to lowest) in Tableau

Tag : sorting , By : Marc
Date : March 29 2020, 07:55 AM
it helps some times So to get this you first need to get a calc field that gets the win %:
``````SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)/COUNTD([Game ID])
``````
``````SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)
``````
``````game-date-id = STR([game]) + STR(' ') + STR(date)
``````
``````SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)/COUNTD([game-date-id])
``````

Displaying highest and lowest number values in C

Tag : c , By : Lucas Thompson
Date : March 29 2020, 07:55 AM
With these it helps In the while loop you are mentioning min=max=grade the second time in the program. That is taking the value of -1 from grade which is used to stop the program. Please comment that line and try it should work.

displaying the lowest and highest of 2d array

Tag : java , By : jsmb
Date : March 29 2020, 07:55 AM