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Creating nested structure xml with django


Creating nested structure xml with django

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Creating nested structure xml with django
Tag : xml , By : n1ckless_id
Date : November 21 2020, 04:03 PM

help you fix your problem I figure out!
So regroup could be nested and my code should be looks like something like this:
{% regroup datas by pagenum as pagenum_list %}
{% for pagenum in pagenum_list %}
<TAGS>
  <PAGE page="{{pagenum.grouper}}">
    {% regroup pagenum.list by parenttag as parenttag_list %}
    {% for parenttag in parenttag_list %}
    <PARENT parent="{{parenttag.grouper}}">
      {% regroup parenttag.list by tag as tag_list %}
      {% for tag in tag_list %}
      <TAG>{{tag.grouper}}</TAG>
      {% endfor %}
    </PARENT>
    {% endfor %}
  </PAGE>
</TAGS>
{% endfor %}

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creating a list from a nested structure in prolog


Tag : prolog , By : rajiv
Date : March 29 2020, 07:55 AM
I hope this helps you . First note that is not a good idea to use a recursive structure the way you have it defined, as it differentiates the last item from the others.
You can do it greedily, assuming that your structure is ordered by the exponents (as your examples show):
structure(Struct, Exps):-
  structure(Struct, 0, Exps).

structure(item(koeffizient(Coeff), exponent(Exp)), Exp, [Coeff]).
structure(item(koeffizient(Coeff), exponent(MExp)), Exp, [0|Tail]):-
  MExp > Exp,
  succ(Exp, NExp),
  structure(item(koeffizient(Coeff), exponent(MExp)), NExp, Tail).
structure(item(koeffizient(Coeff), exponent(Exp), StructTail), Exp, [Coeff|Tail]):-
  succ(Exp, NExp),
  structure(StructTail, NExp, Tail).
structure(item(koeffizient(Coeff), exponent(MExp), StructTail), Exp, [0|Tail]):-
  MExp > Exp,
  succ(Exp, NExp),
  structure(item(koeffizient(Coeff), exponent(MExp), StructTail), NExp, Tail).
structure([], _, []).
structure([Exp-Coeff|Tail], Exp, [Coeff|TailCoeffs]):-
  succ(Exp, NExp),
  structure(Tail, NExp, TailCoeffs).
structure([MExp-Coeff|Tail], Exp, [0|TailCoeffs]):-
  MExp > Exp,
  succ(Exp, NExp),
  structure([MExp-Coeff|Tail], NExp, TailCoeffs).

Django - loop over this nested structure in a django template


Tag : django , By : Trevor Cortez
Date : March 29 2020, 07:55 AM
Does that help Here is my data structure. , You can do something like this in your template:
{% for my_dict in var.a %}
    {# my_dict now holds the value of var['a'] #}
{% endfor %}

{% for key, my_list in var.b.items %}
    {# key is the key from var['b'], and my_list is the value associated with it #}
    {% for my_dict in my_list %}
        {# Now, my_dict is one dict from the list in var['b'][key]. #}
    {% endfor %}
{% endfor %}

Creating Nested Object Firebase structure


Tag : android , By : rhinojosa
Date : March 29 2020, 07:55 AM
around this issue I'm using Firebase as my database for my Android project. In this project, I have users with minimal data associated with them. , These seem to be the minimal classes needed for your data:
public class Event {
  public String name;
  public Long startTime;
  public Long endTime;
}

public class User { 
  public String Display;
  public String Email;
  public Map<String, Event> Schedule;
}

Creating nested arrays of set structure


Tag : javascript , By : boonchew
Date : March 29 2020, 07:55 AM
With these it helps Ok, I want to have my try as well! Why did nobody think about reduce? It's faster than for-loop! And more elegant. IMO at least.
So I've done few tests, and here are results:
const array2 = array1.reduce((arr, obj) => {
  if (obj.hasOwnProperty('town1') && obj.hasOwnProperty('town2') && obj.hasOwnProperty('value')) {
    arr.push([ { name: obj.town1, value: obj.distance }, { name: obj.town2 } ])
  }

  return arr
}, [])
const array2 = array1.reduce((arr, obj) => (
  (obj.hasOwnProperty('town1') && obj.hasOwnProperty('town2') && obj.hasOwnProperty('value'))
    ? Array.prototype.concat(arr, [[ { name: obj.town1, value: obj.distance }, { name: obj.town2 } ]])
    : arr
  ), [])
array2 = array1.reduce((arr, obj) => (
  (obj.hasOwnProperty('town1') && obj.hasOwnProperty('town2') && obj.hasOwnProperty('value'))
    ?  [...arr, [ { name: obj.town1, value: obj.distance }, { name: obj.town2 } ]]
    : arr
  ), [])
for (let i = 0; i<array1.length; i++) {
  if (array1[i].hasOwnProperty('town1') && array1[i].hasOwnProperty('town2') && array1[i].hasOwnProperty('distance')) {
    array2.push([{name:array1[i]['town1'], value: array1[i]['distance']}, { name: array1[i]['town2']}])
  }
}

Creating query in nested django model and group the results in django


Tag : python , By : user126922
Date : March 29 2020, 07:55 AM
Hope this helps We can "ship" the ip_address of the related Device with our query and perform the grouping at the Django level, for example with itertools.groupby, like:
from django.db.models import F
from itertools import groupby
from operator import attrgetter

qs = Port.objects.annotate(
    ip_addr=F('host__ip_addr')
).filter(
    host__report_id=pk
).order_by('ip_addr')

result = {
    k: list(vs)
    for k, vs in groupby(qs, attrgetter('ip_addr'))
}
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