Take class which implements interface

Take class which implements interface

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Take class which implements interface
Tag : chash , By : chudq7
Date : September 16 2020, 10:00 AM

it should still fix some issue I have an abstract base model class which contains some shared properties. On top of that I have a number of minor interfaces, which defines what processes a model will be available for. , You can get some of the way there with generics:
public class ProcessorA<TModel> : ProcessorBase where TModel : ModelBase, ISupportProcessA
    private readonly ISupportProcessA model;

    public ProcessorA(TModel model) : base(model)
        this.model = model;

    // ...some specific methods
public abstract class ProcessorBase
    protected abstract ModelBase ModelForBase { get; }

    // ...some shared methods

public abstract class ProcessorA : ProcessorBase
    public static ProcessorA Create<TModel>(TModel model) where TModel : ModelBase, ISupportProcessA
        return new ProcessorA<TModel>(model);

    // Abstract specific methods
    public abstract void SomeSpecificMethod();

public class ProcessorA<TModel> : ProcessorA where TModel : ModelBase, ISupportProcessA
    protected override ModelBase ModelForBase => model;

    private readonly TModel model;

    public ProcessorA(TModel model)
        this.model = model;

    // Specific method overrides
    public override void SomeSpecificMethod()

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Should a java class x that extends class y, which implements interface z, also implement interface z

Tag : java , By : KS9
Date : March 29 2020, 07:55 AM
Hope this helps No. If the interface is implemented somewhere in the hierarchy of your current class, then that is enough.
In the end, an interface just defines a few methods that a class should contain. To your subclass this is no different than if it were "normal" methods from the top class.
public class Main {
    public static void main(String[] args) {
        new X().test();
        new Y().test();

class X extends Y{


class Y implements Z{
    public void test() {
        System.out.println("in Y");

interface Z {
    public void test();
class X extends Y implements Z

Cyclic inheritance and interfaces - class A can't implement class B interface while class B implements A interface

Tag : java , By : Jesse
Date : March 29 2020, 07:55 AM
wish of those help I have: , It may help to draw it out.
is part of  /     \    inherits
   AListener        BListener
  inherits  \     /    is part of 

How to pass an Object of a Class that implements an Interface with just knowing the Class of the Interface to a Method a

Tag : java , By : kgw
Date : March 29 2020, 07:55 AM
Hope this helps Lets say that I have an Interface and multiple Classes that implement this Interface: , As per generics for ? extends MyInterface only getters are allowed
ArrayList<? extends MyInterface> objects = new ArrayList<>();
you can only do get of type MyInterface and Object
MyInterface myInterace = objects.get(0);
Object myInterace = objects.get(0);
Long longValue = 20L; 
List<Long> longList = new ArrayList();

Integer i =10;
List<? extends Number> sNumber = longList ;// longList can be assigned to ? extends Number
sNumber.add(i); // if this was allowed
longValue = longList.get(1);   // we will get an exception (class cast exception)

Does a class inherit an abstract inner class declared within an interface when the class implements that interface?

Tag : java , By : Joe
Date : March 29 2020, 07:55 AM
seems to work fine A member class defined inside an interface is always implicitly static. It's not an inner class, but a static member class, and it doesn't have an outer class instance associated with it.
The Java Language Specification states this in section 9.5:

Adapting a Class to an Interface when it implements all of the interface but doesn't declare the interface

Tag : chash , By : chintown
Date : March 29 2020, 07:55 AM
hope this fix your issue Yes, the 3 methods you've done is all you need. A dictionary allegedly relies mostly on the hashcode.
However your cast in Equals(object obj) will go wrong: it will cast a Booh to null. You want to test/cast both FooBar and just plain T.
    bool Equals(FooBar<T> other)
        return EqualityComparer<T>.Default.Equals(Value, other.Value);

    public override bool Equals(object obj)
        if (ReferenceEquals(null, obj)) return false;
        if (ReferenceEquals(this, obj)) return true;
        if (obj is T) return Value.Equals(obj);
        if (obj.GetType() != this.GetType()) return false;
        return Equals((FooBar<T>) obj);

    public override int GetHashCode()
        return EqualityComparer<T>.Default.GetHashCode(Value);
    public void CanUseInDict()
        var foobar= new Booh();
        IFooBar[] foobars= new IFooBar[]{ foobar.AsIFooBar() };
        Dictionary<IFooBar,string> ifoobars= new Dictionary<IFooBar, string>()
            { foobar.AsIFooBar(), foobar.GetType().Name}

        Assert.Equal( foobar.GetHashCode(),  new FooBar<Booh>( foobar ).GetHashCode());
        Assert.True( foobar.AsIFooBar().Equals( new FooBar<Booh>( foobar ) )  , "Equals FooBar<Booh>");
        Assert.True( ifoobars.ContainsKey( new FooBar<Booh>(foobar) ), "ContainsKey");            

static class BoohFooBarExt
    public static IFooBar AsIFooBar<T>(this T value ) where T:IFoo, IBar => new FooBar<T>(value);
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