Remove a negative element from an array w/o array.copy

Remove a negative element from an array w/o array.copy

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Remove a negative element from an array w/o array.copy
Tag : java , By : PatrickSimonHenk
Date : November 26 2020, 01:01 AM

I wish this helpful for you If you simply want to remove all the negative elements in the Array you can do:
arr = Arrays.stream(arr).filter(e -> e >= 0).toArray();

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Copy to new array and remove element?

Tag : javascript , By : meodudang
Date : March 29 2020, 07:55 AM
Any of those help Use slice() to copy the values to the new array:
var m2 = m1.slice(0);

if an array is -5 4 1 , how to remove the negative sign of 5 and make it a complete non-negative array as 5 4 1

Tag : c , By : jrf
Date : March 29 2020, 07:55 AM
it fixes the issue If an element in the array is less than zero, multiply it by -1. Don't turn it into an unsigned number, that's probably not going to do what you think it does. Also, as mentioned, what you are doing in your code snippet isn't even modifying the element in the array, it's trying to declare a new array. So basically you should do:
if arr[element] < 0 {
    arr[element] *= -1;

How to remove an element in a character array or create a copy of a new array without specific elements?

Tag : c , By : Dean
Date : March 29 2020, 07:55 AM
Any of those help Rather than trying to update the string you have, just print out a character if it's a letter.
Also, upper case and lower case characters don't immediately follow one another, so you need to check for them separately:
printf(" Your new message is: ");
for(int i = 0; i< strlen(my_array);i++)
    if((my_array[i] >= 'A' && my_array[i] <= 'Z') || 
       (my_array[i] >= 'z' && my_array[i] <= 'z'))
if (isalpha(my_array[i]))

Ruby - Loop through an array , Remove end element of that array and append it to another array

Tag : arrays , By : Alex Bartzas
Date : September 28 2020, 01:00 PM
Any of those help The simplest/clearest solution to reach your desired output (nondestructively):
drink + food.reverse
until food.empty?
  drink << food.pop
drink << food.pop until food.empty?

Copy the last element of an array into a different position, and then remove it from the end of the array

Tag : javascript , By : Mark W
Date : September 25 2020, 08:00 PM
Any of those help I'm looking for a neat (single-statement) method for copying the last element of an array into a different position (overriding an existing element), and then removing it from the end of the array. , You can try this:
function func(array, index) {
    array[index] = array.pop();
    return array;

// Or
// const func = (array, index) => (array[index] = array.pop(), array);

const arr = func([1,2,3,4], 1);

function func(array, index) {
    if(index < array.length -1) array[index] = array.pop()
    else array.pop();
    return array;

// Or
// const func = (array, index) => (index < array.length -1 ? array[index] = array.pop() : array.pop(), array);

console.log(func([1,2,3,4], 1));

console.log(func([1,2,3,4], 3));
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