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(Python 2.7) Access variable from class with accessor/mutator


(Python 2.7) Access variable from class with accessor/mutator

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(Python 2.7) Access variable from class with accessor/mutator
Tag : python , By : walkah
Date : November 24 2020, 05:44 AM

this will help This is because you are accessing the class instead of an object of that type.
Let's try it on a minimal example:
class Container:
    def __init__(self):
        self._content = range(10)

    @property
    def content(self):
        return self._content

    @content.setter
    def set_content(self, c):
        self._content = c
c = Container()
for number in c.content:
    print(number)
for number in Container.content:
    print(number)
TypeError        Traceback (most recent call last)
<ipython-input-27-f1df89781355> in <module>()
      1 # This doesn't:
----> 2 for number in Container.content:
      3     print(number)

TypeError: 'property' object is not iterable
class Container:
    def __init__(self):
        self.container = range(10)
for number in Container().content:  # note the '()'!!
    print(number)

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Accessor & Mutator methods (Python)


Tag : python , By : user180941
Date : March 29 2020, 07:55 AM
it helps some times With myCar.set_make=('Porche'), you are setting this member the Car class as the 'Porche' string, but you are not calling the method.
Just remove the = to solve it:
myCar.set_make('Porche')
myCar.get_make() # Porche
def set_make(self, make):
    self.__make = make # carMake is not defined!

Moving accessor and mutator methods from one class into its superclass


Tag : java , By : cynix
Date : March 29 2020, 07:55 AM
like below fixes the issue You can't put a function call on the left-hand side of an assignment. That just doesn't make sense.
If medication weren't private, you could just have your method assign to it. Since it's private, you can't. There are two solutions:

Class accessor and mutator functions in c++


Tag : cpp , By : Will
Date : March 29 2020, 07:55 AM
wish helps you Don't pass the functions the argument type: obj.set_account(i) and obj.output(cout) are sufficient. Notice that I passed cout instead of out because out is not defined in main(). Remember, the parameter name in the function definition/declaration has nothing to do with the name of the argument that you actually pass it.
You're also missing return types for your function definitions.

Python accessor and mutator methods


Tag : python , By : ezzze
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You've created the blueprint for your objects. That's your Person class. Now it's time to build some Person's. You can do that with
p1 = Person("Your Name", "Address", 12, "phone_number")
p2 = etc
p3 = etc
p1.set_name("Joe")
print(p1.get_name()) # outputs "Joe"

Accessor and mutator c++ method in class arrray [3][3]


Tag : cpp , By : esimran
Date : March 29 2020, 07:55 AM
seems to work fine I am a beginner programmer, I have a problem with the task. I have to use method set(), get() to initialize elements of matrix [3][3], but I have to make universal method for all elements. , The getter/setter methods:
void setElement(const unsigned row, const unsigned col, const float value) 
{data[row][col] = value;}

float getElement(const unsigned row, const unsigned col) const
{return data[row][col];}
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