printf following zeros to a certain degree

printf following zeros to a certain degree

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printf following zeros to a certain degree
Tag : c , By : Gerhard Miller
Date : January 02 2021, 06:48 AM

it fixes the issue
How would I make the actual calculation fill in zeros to the end of the string?
printf("%1.9f%071d\n", pi, 0); // Print an extra int 0 with wide width padded with '0'
printf("%1.80f\n", pi);        // Print with wide precision - (might not all be 0's)
#define PI_STR "3.1415926535" \
printf("%s\n", "References:\n" PI_STR);

// Remember length of reference pi string
int pi_ref_len = (sizeof PI_STR)  - 1;

// Print computed pi & return count of characters printed
int pi_compute_len = printf("%1.9f", pi);

// Use a loop or print a portion of a string "0000...000"
char zeros[sizeof PI_STR];
memset(zeros, '0', sizeof zeros);
//        v--- %s w/precision can print a non-null character terminated char array
printf("%.*s\n", pi_ref_len - pi_compute_len, zeros);

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printf with leading zeros in C

Tag : c , By : user178709
Date : March 29 2020, 07:55 AM
I wish this helpful for you Your format specifier is incorrect. From the printf() man page on my machine:
#include <stdio.h>

int main(int argc, char **argv)
  printf("%09.3f\n", 4917.24);
  return 0;
$ make testapp
cc     testapp.c   -o testapp
$ ./testapp 

Using printf to add zeros to an integer value

Tag : java , By : Carter
Date : March 29 2020, 07:55 AM
should help you out You can do something like this:
String formatted = String.format("%03d", num);
 public static void main(String[] args){
    String word = "Word";

    int num = 5;
    System.out.printf("%-10s  %03d\n" , word, num);

    num = 55;
    System.out.printf("%-10s  %03d\n" , word, num);

    num = 555;
    System.out.printf("%-10s  %03d\n" , word, num);

    num = 5555;
    System.out.printf("%-10s  %03d\n" , word, num);

    num = 55555;
    System.out.printf("%-10s  %03d\n" , word, num);
mike@switters:~/code/scratch$ javac Pf.java && java Pf
Word        005
Word        055
Word        555
Word        5555
Word        55555

How to calculate in-degree, out-degree and weigted degree for force directed graph (d3.js)?

Tag : javascript , By : Bimal Poudel
Date : March 29 2020, 07:55 AM
Any of those help D3 automatically computes the node degree and puts it in a new attribute .weight. The weighted graph is already given by the values of the edges. The in and out degrees can be computed easily:
nodes.forEach(function(d) {
  d.inDegree = 0;
  d.outDegree = 0;
links.forEach(function(d) {
  nodes[d.source].outDegree += 1;
  nodes[d.target].inDegree += 1;

Printf only returns zeros

Tag : c , By : user187301
Date : March 29 2020, 07:55 AM
hop of those help? I'm sitting right in front of my computer but I don't have a clue where my mistake is. So here is my code in C: , Change this:
scanf("&lf", &x);
scanf("%lf", &x);
printf("%", f(x));
printf("%lf", f(x));
prog.c: In function 'main':
prog.c:11:11: warning: too many arguments for format [-Wformat-extra-args]
   11 |     scanf("&lf", &x);
      |           ^~~~~
prog.c:13:13: warning: spurious trailing '%' in format [-Wformat=]
   13 |     printf("%", f(x));
      |             ^
prog.c:13:12: warning: too many arguments for format [-Wformat-extra-args]
   13 |     printf("%", f(x));
      |            ^~~

printf aligning problem with degree (°) character

Tag : perl , By : can
Date : March 29 2020, 07:55 AM
hop of those help? UTF-8 only maps the ASCII range (0..127) to 1 byte. Latin-1 characters are in the range 0..255; UTF-8 can't map them all to one byte. If it did, there would be no mappings left for anything else.
Characters from 0 to 127 are encoded in 1 byte.

use strict;
use warnings;
use utf8;

    binmode STDIN,  ':encoding(UTF-8)';
    binmode STDOUT, ':encoding(UTF-8)';
    binmode STDERR, ':encoding(UTF-8)';

printf "|%-10s|\n", "x";
printf "|%-10s|\n", "°";
|x         |
|°         |
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