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Execute mulltiple expressions in conditional operator


Execute mulltiple expressions in conditional operator

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Execute mulltiple expressions in conditional operator
Tag : php , By : user184415
Date : December 05 2020, 12:18 PM


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Expressions with conditional and assignment operator


Tag : java , By : Brazen
Date : March 29 2020, 07:55 AM
I wish this help you Here are the two keys to understanding the difference between the JavaScript conditional expression and the Java conditional expression:
Please read the Note at the bottom of this section of the ECMAScript 5 annotated specification:
1
operand1 ? operand2 : operand3;
(function () { if (operand0) return operand1; else return operand2;}());
false ? 1 : x = 2;
(function () { if (false) return 1; else return x = 2;}());
(false ? 1 : x) = 2;
(function () { if (false) return 1; else return x;}()) = 2;
3 = 2;
var x = 3;

console.log(false ? 1 : x);          // ?: evaluates to "3"
console.log(false ? 1 : x = 2);      // ?: evaluates to "2"
console.log(false ? 1 : x = 2, 4);   // ?: evaluates to "2" - "2" and "4" arguments passed to log
console.log((false ? 1 : x = 2, 4)); // ?: evaluates to "4"
console.log((false ? 1 : x = 2), 4);

declaring a variable within conditional expressions (ternary operator)


Tag : javascript , By : Paolo
Date : March 29 2020, 07:55 AM
it helps some times
Is it possible to declare the variable within a conditional expression?

Is there something like the conditional operator but for expressions?


Tag : chash , By : terrestrial
Date : March 29 2020, 07:55 AM
hop of those help? If both methods have same signature (same parameters and same return type) you can do this. for example if both methods are void and take no parameters
(special ? (Action)Foo : Bar).Invoke();
(special ? (Action<int>)Foo : Bar).Invoke(20);
bool result = (special ? (Func<int, string, bool>)Foo : Bar).Invoke(20, "...");

Does Groovy's ternary conditional operator have a bug in string expressions?


Tag : groovy , By : Brownell
Date : March 29 2020, 07:55 AM
will help you It's all to do with operator precedence.
Most* languages have a rule of precedence for operators (which ones are taken first when there are multiple options). Groovys order can be found here.
('a' + f) ? 'b' : ('z' + 'c')
('atrue') ? 'b' : ('zc')

what does the ampersand operator do in python in conditional expressions?


Tag : python , By : Kenny
Date : March 29 2020, 07:55 AM
wish of those help This is the result of a badly-configured HTML escaping tool which somehow managed to escape the code twice. It's supposed to be >=.
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