Strange Segmentation fault of function strcpy in linux c program
Date : March 29 2020, 07:55 AM
I wish this help you s[off] = *s is wrong in the first loop. s[off] points the address s + off, which in the first loop is: s + off = s + (dest - s - 1) = dest - 1
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Program crashes after perfoming strcpy() function
Date : March 29 2020, 07:55 AM
To fix the issue you can do The problem is with the newline left in the file after the initial fscanf() call. This fscanf(fp,"%d",&n);
char str[256];
fgets(str, sizeof str, fp);
sscanf(str, "%d", &n);
for(i=0; i<n; i++)
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Need help understanding this C program which simulates strcpy() with a function
Tag : c , By : Matt Logan
Date : March 29 2020, 07:55 AM
I wish this helpful for you The characters in the ASCII table assume values that range from 0 to 127, 0 being NULL or '\0', so the condition is always true unless the character is '\0'.
*d = 0 places a '\0' at the end of the string; it's how strings are terminated in C. If you don't terminate the string, anything can be printed past the end of the string, and the program has no way to know where it ends. It's undefined behaviour.
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Alternative to strcpy? or fix to strcpy in program?
Date : March 29 2020, 07:55 AM
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Why does the strcpy() function produce unwanted outputs in the case of this program?
Date : March 29 2020, 07:55 AM
This might help you When you define a pointer like char *name; it points to some random location as you haven't initialized it. It is illegal to write to the pointer and doing so will invoke Undefined Behavior.
strcpy basically writes the string to this random pointer location invoking UB.
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