preg_replace php to replace repeated characters
Tag : php , By : barefootChild
Date : March 29 2020, 07:55 AM
Hope that helps So I have a list of values like that goes like this: , No need for regex for this: join(",", array_unique(split(",", $values)))
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How to replace repeated pattern of characters
Date : March 29 2020, 07:55 AM
wish helps you You need backreferences here in order to repeat the match that was actually made, as opposed to trying to make a new match with the same pattern: ([a-z0-9]{2})\1\1
>>> import re
>>> re.sub(r'([a-z0-9]{2})\1\1', r'', "abababwhatevercdcdcd")
'whatever'
>>> re.sub(r'([a-z0-9]{2})\1\1', r'', "wabababhatevercdcdcd")
'whatever'
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Regex to replace repeated characters
Date : March 29 2020, 07:55 AM
Hope this helps Can someone give me a Java regex to replace the following. , Change your regex like below. string.replaceAll("((.)\\2{2})\\2+","$1");
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Reducing repeated characters in a string while having a maximum number of repeated characters allowed
Date : March 29 2020, 07:55 AM
may help you . I have no idea how I would even begin to tackle this problem, , Simple solution: void x(char *s, int n)
{
char *cp= s;
int i, j;
while (*cp) {
i= 1;
while (*(cp+i) && ((*(cp+i))&~32)==((*cp)&~32)) i++; // count character repeat
for (j=0; j<n && j<i; j++) // repeat at most max repeat (n)
*s++ = *(cp+j);
cp += i;
}
*s= '\0';
}
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How to group repeated characters by number of the times those got repeated?
Date : October 05 2020, 08:00 AM
I hope this helps you . Objective: , Try (we use characters as keys in h={} and count them) const randomChars = 'ABaaBCDdeGFAAR';
let h= {};
randomChars.toUpperCase().split('').forEach(c => h[c]=++h[c]||1);
let r = Object.keys(h).sort().map(k => h[k]+k).join(' ');
console.log(r);
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