Python search and copy files in directory

Python search and copy files in directory

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Python search and copy files in directory
Tag : python , By : Cosmin
Date : November 28 2020, 01:01 AM

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search given set of files and copy to another directory

Tag : windows , By : ChaseVoid
Date : March 29 2020, 07:55 AM
will help you Format needToFind.txt to have one file name per line. The following simple batch script should work.
@echo off
cd "\MyImageFolder"
for /f "usebackq eol=: delims=" %%F in ("needToFind.txt") do copy "%%~F" "\anotherFolder"

Makefile: copy perl/python files from source directory into build directory

Tag : cpp , By : ChaseVoid
Date : March 29 2020, 07:55 AM
Any of those help Basically, when you run make X, you are telling Make to find target X in your Makefile. So if you have no install: target, nothing will happen. All of this really depends what is in your Makefiles. If you want to copy your perl/python files into the build directory, one way to do so is to write a Makefile target that runs a *sh command like mv dir2/*.pyc build; mv dir2/*.pl build, and require that target somewhere else in your Makefile. If you need a good Makefile tutorial, here's one that I started with.

Python: Loop through directory, check if certain amount of files is in there, if not; copy 2 files from other directory

Tag : python , By : akr
Date : March 29 2020, 07:55 AM
it helps some times Your specs are pretty vague, so I had to assume a lot of things. I think this code achieves what you want, but you may have to tweak it a bit (for example date format in the directory name).
I assumed a directory structure like this:
c:\new (base dir)
import os
import fnmatch
import time
import shutil
import re

# directories    
base_dir = "C:\new"
standard_dir = os.path.join(base_dir, "standard")

# find files in directory. based on yours, but modified to return a list.
def find_dir(path, name_filter):
    result = []
    for root, dirs, files in os.walk(path):
        for filename in fnmatch.filter(files, name_filter):
            result.append(os.path.join(root, filename))
    return result

# getting today's directory. you can rearrange year-month-day as you want.
def todays_dir():
    date_str = time.strftime("%Y_%m_%d")
    return os.path.join(base_dir, "daily_" + date_str)

# copy a file from one directory to another
def copy(filename, from_dir, to_dir):
    from_file = os.path.join(from_dir, filename)
    to_file = os.path.join(to_dir, filename)
    shutil.copyfile(from_file, to_file)

# main logic
today_dir = todays_dir()
pdfs = find_dir(today_dir, "*.pdf")
excels = find_dir(today_dir, "*.xls")
if len(pdfs) == 0:
    copy("standard1.pdf", standard_dir, today_dir)
    copy("standard2.pdf", standard_dir, today_dir)
    if len(excels) == 1:
        excel_name = os.path.splitext(excels[0])[0]
        excel_num = re.findall(r"\d+", excel_name)[-1]
        copy(excel_num + ".pdf", standard_dir, today_dir)

UNIX: How to search and copy all files with the same name to a different directory

Tag : bash , By : bikefixxer
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I thought I would put this out here to help anyone else who may need it. , A simple bash for-loop could achieve this:-
for file in $(find folder/ -name "$fileName" -type f -printf '%P\n'); 
  sourcePath=$(dirname $(readlink -f "$file")) 
  cp -v $sourcePath/$fileName /new/location/"$fileName$COUNTER" 
$ find . -name "spreadsheet.csv" -type f

 $ ./script.sh
`/home/dude/foo/spreadsheet.csv' -> `/new/location/spreadsheet.csv0'
`/home/dude/bar/spreadsheet.csv' -> `/new/location/spreadsheet.csv1'
`/home/dude/woo/spreadsheet.csv' -> `/new/location/spreadsheet.csv2'
`/home/dude/spreadsheet.csv' -> `/new/location/spreadsheet.csv3'

Search for Files with Extension and Copy to Directory in Python?

Tag : python , By : anon
Date : March 29 2020, 07:55 AM
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