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Pasting character vectors, removing NA's and separators between NAs


Pasting character vectors, removing NA's and separators between NAs

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Pasting character vectors, removing NA's and separators between NAs
Tag : regex , By : mux
Date : November 27 2020, 01:01 AM


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Pasting two vectors with combinations of all vectors' elements


Tag : r , By : user161380
Date : March 29 2020, 07:55 AM
Does that help I have two vectors: , You can use this, but there may be a simpler solution :
R> apply(expand.grid(vars, vis), 1, paste, collapse=".")
[1] "SR.1" "PL.1" "SR.2" "PL.2" "SR.3" "PL.3"
as.vector(outer(vars, vis, paste, sep="."))
# [1] "SR.1" "PL.1" "SR.2" "PL.2" "SR.3" "PL.3"

Pasting elements of two vectors alphabetically in r


Tag : r , By : shehan
Date : March 29 2020, 07:55 AM
wish helps you Say I have two vectors: , Here's one approach:
apply(cbind(a, b), 1, function(x) paste(sort(x), collapse=" "))

## [1] "george harry" "harry steve"  "chris harry"  "chris harry"  
## [5] "harry steve" "george steve" "chris steve"  "george harry"
unlist(Map(function(x, y) paste(sort(c(x, y)), collapse=" "), a, b),,FALSE)
mapply(function(x, y) paste(sort(c(x, y)), collapse=" "), a, b, USE.NAMES = FALSE)

pasting together two vectors with expression command


Tag : r , By : Peter Leung
Date : March 29 2020, 07:55 AM
seems to work fine This is a bit tricky because the expression function expects a list of expressions. Therefore you need to convert the strings returned by paste to a list of unevaluated expressions. One way is like this
together <- do.call(expression, as.list(parse(text = paste0("italic(", t, ")~", n))))

Creating several new vectors from an original vector with separators


Tag : r , By : Cosmin
Date : March 29 2020, 07:55 AM
Does that help I'm trying to create several vectors from an original vector. I read some posts but couldn't find something to solve my problem. , This should work:
x <- c("A",  "B",  "C",  "D;", "1",  "2;", "a1", "a2", "a3")

sapply(split(x, c(0, cumsum(grepl(";", x))[-length(x)])), function(x) gsub(";", "", x))

$`0`
[1] "A" "B" "C" "D"

$`1`
[1] "1" "2"

$`2`
[1] "a1" "a2" "a3"

I need to split a string based on some character array of separators and not lose these separators in string


Tag : chash , By : Sebastian Gift
Date : March 29 2020, 07:55 AM
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