Easiest way to extract 4 digit number out of string?

Easiest way to extract 4 digit number out of string?

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Easiest way to extract 4 digit number out of string?
Tag : .net , By : yossi
Date : November 27 2020, 01:01 AM

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extract 9 digit number from a string

Tag : php , By : Paul
Date : March 29 2020, 07:55 AM
will help you I basically have an array in php which contains a string, I basically need to filter the string in order to get a 9 digit ID number (which is surrounded by brackets), im sure there could be a way to do this with regex but im clueless. , by using preg_replace you just have one line filter....
 $str['task'] = preg_replace('/.*\((\d{9})\).*/', '$1', "meeting mike (298124190)");
$strings = array("meeting mike (298124190)", "meeting mike (298124190)", "meeting mike (298124190)");
foreach ($strings as $string) {
    if (preg_match("|\(([\d]{9})\)|", $string, $matches)) {
        $str[] = $matches[1];
        // OR $str['task'][] = $matches[1];

Regex Help. String with no spaces, but 5 digit number in center. Extract the number only. PHP

Tag : php , By : Michael T.
Date : March 29 2020, 07:55 AM
Hope this helps Sample string , Another solution for your specific type of string: where
$text_array = explode("<br_SPACE_/>", $text);
$array1 = explode("_SPACE_", $text_array[0]);
echo $array1[0] . ' and ' . $array1[1];
$number = trim($text_array[1], "__SPACE__");
echo '<br>and ' . $number;

$array1[0] is the 'Rpt#'
$array1[1] is the 'MINVTAN'
$number is '01212'

regex - Extract number from string. Number should be first 5 digit from my input

Tag : java , By : Ed.
Date : March 29 2020, 07:55 AM
will help you You may capture the value you need into a capturing group and access it with the corresponding code.
The regex for both Java and Python can look like
String s = "Install: C:\\Program Files\\app\nDatabase: postgresql://\nStarted: 2016-12-28 10:40:05.908000\nLines: 1000000\nVersion: 4.1\nPID: 1736";
Pattern pattern = Pattern.compile("postgresql://[\\d.]+:(\\d+)\\b");
Matcher matcher = pattern.matcher(s);
if (matcher.find()){
import re
s = "Install: C:\\Program Files\\app\nDatabase: postgresql://\nStarted: 2016-12-28 10:40:05.908000\nLines: 1000000\nVersion: 4.1\nPID: 1736";
pattern = r"postgresql://[\d.]+:(\d+)\b"
m = re.search(pattern, s)
if m:

How to extract only 6 digit number from a random String message? 6 digit number is not in the beginning or end of the me

Tag : java , By : FuzzyHornet
Date : March 29 2020, 07:55 AM
will help you You can extract any 6 digit number from any String message. "|" is used to lookup more possible combinations. Only "\d{6}" also give you the correct result for your problem.
//find any 6 digit number
Pattern mPattern = Pattern.compile("(|^)\\d{6}");

if(message!=null) {
    Matcher mMatcher = mPattern.matcher(message);
    if(mMatcher.find()) {
        String otp = mMatcher.group(0);
        Log.i(TAG,"Final OTP: "+ otp);
    }else {
        //something went wrong
        Log.e(TAG,"Failed to extract the OTP!! ");

SQL query/function to extract the first number from a string? not just the 1st numerical digit but the entire number unt

Tag : sql , By : tanminivan
Date : March 29 2020, 07:55 AM
I wish this help you I have two input strings that look like 'London 350 Paris 456 eu iu' and 'New York 154 Seattle 890 pc appl iu'. , In this way you can get the First number.
DECLARE @VAR VARCHAR(MAX) = 'London 350 Paris 456 eu iu'

SELECT SUBSTRING(@VAR, PATINDEX('%[0-9]%', @VAR), PATINDEX('%[^0-9]%', SUBSTRING(@VAR, PATINDEX('%[0-9]%', @VAR), 100)))
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