TR alternate background colour with unequal number of TD

Hope that helps Define the styles so that your unique color is defined later in the stylesheet, like this:

tbody tr.alt td {
  background-color: #e6EEEE;
}
tbody tr td.coloron {
  background-color: #FFFFFF;
}

help you fix your problem You can use a converter - grab a row index from an item and convert it to a brush. Also - if ItemTemplate does not give you enough control - use ItemContainerStyle to modify the brush at the ListViewItem template level.
Another option might be to specify an ItemTemplateSelector that gives you a different template with a different brush depending on an item. You would still need to generate row indices though or somehow enable the selector to determine if the item is at an even or odd position.

I hope this helps . Just use modulus two:

$postcolour = $counter % 2 ? 'lightblue' : 'darkblue';

I hope this helps . I am using: , Figured it out! I used:

a:hover.altlink{
    color: #FF0000;
}

hop of those help? If I understood correctly what you want,then you want to target your div's not divs inside them :

div.G:nth-child(even) {background: #CCC;}
div.G:nth-child(odd) { background: #FFF;}