Java Regex Help: Splitting String on spaces, "=>", and commas
Tag : java , By : ArmHead
Date : March 29 2020, 07:55 AM
I hope this helps . Just create regex matching any of your three cases and pass it into split method: string.split("\\s*(=>|,|\\s)\\s*");
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Regex exclude doesn't exclude string only first character
Date : March 29 2020, 07:55 AM
hope this fix your issue The point is that the } is matched since your (?!{ignoreme}) lookahead only skips a { followed with ignoreme} and matches a } since it is not starting a {ignoreme} char sequence. Also, in JS, you cannot use a lookbehind, like (?This is a kind of issue that can be handled with a regex that matches what you do not need, and matches and captures what you need: /{ignoreme}|([\s[\]{}()<>\\'"|^`])/g
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Regex: Identify file name with "string" but exclude if has .filepart extension
Tag : regex , By : Michael
Date : March 29 2020, 07:55 AM
With these it helps I have a requirement to search through a directory to identify specific files with a string contained in the file name. But I want to exclude part loaded files with a ".filepart" extension. , Your original regex is: .*FILETYPE.*\.[[:alnum:]]*(?!filepart)
.*FILETYPE.*
.*FILETYPE.*(?<!filepart)$
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Is there a regex which will generate a String array by splitting a line for the first two spaces (" ") and the
Tag : java , By : Jay Crockett
Date : March 29 2020, 07:55 AM
may help you . I have the following text file: , You can try this regex: (\\d+) ([A-Z][a-z]+) (.+)
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RegEx to exclude directory, capture filename that are separated by commas, exclude "(number)" and extensions
Tag : python , By : Antony Briggs
Date : March 29 2020, 07:55 AM
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