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I need help not using brute force when using JFrames and DrawWindows


I need help not using brute force when using JFrames and DrawWindows

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I need help not using brute force when using JFrames and DrawWindows
Tag : java , By : user183289
Date : November 26 2020, 01:01 AM


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Anyway to do this puzzle that's not brute force (and how do you brute force)?


Tag : algorithm , By : Habikki
Date : March 29 2020, 07:55 AM
wish of those help You should work problems like this backwards.
Given all the possible game states, go through and decide which is a win for player 1 (W) and which is a win for player 2 (L). Initially, you only know the answer for the states where no one can play. In this case the answer is
X X X X X X (L - terminal)
X X _ X X _ (W - terminal)
_ X X _ X X (W - terminal)
_ X X X X _ (W - terminal)
X X X X _ _ (L - must move to X X X X X X)
_ _ X X X X (L - must move to X X X X X X)
X X _ _ _ _ (L - can move to X X X X _ _) 
_ X X _ _ _ (W - must move to _ X X _ X X or _ X X X X _)
_ _ X X _ _ (L - can move to X X X X _ _)
_ _ _ X X _ (W - must move to X X _ X X _ or _ X X X X _)
_ _ _ _ X X (L - can move to X X _ _ X X)
_ _ _ _ _ _ (W - can move to _ X X _ _ _)
// STORE NUMBER OF ONES
int m = 0;
for (int i=0; i<n; ++i)
    m += P[i];
// LOOK FOR LEGAL MOVES
bool canMove = false;
for (int i=0; i<n-1; ++i)
    int[] newP = P;
    if (P[i]+P[i+1] == 0) {
        canMove = true;
        newP[i] = 1;
        newP[i+1] = 1;
        // PLAYER ONE CAN MOVE TO WIN
        if (m % 4 == 0 && doesPlayerOneWin(newP))
            return true;
        // PLAYER TWO CAN MOVE TO WIN
        if (m % 4 == 2 && !doesPlayerOneWin(newP))
            return false;
     }
}
// IF NO LEGAL MOVES, PLAYER TO MOVE WINS
if (!canMove && m % 4 == 0)
    return true;
else if (!canMove && m % 4 == 2)
    return false;
// OTHERWISE IF LOOP RUNS, PLAYER TO MOVE LOSES
if (m % 4 == 0)
    return false;
else
    return true;

Brute Force- c#


Tag : chash , By : user107021
Date : March 29 2020, 07:55 AM
hop of those help? That's because the program in the video is running the brute force loop in a separate thread.
In your program the loop runs in the main thread, so as long as it's running there is no thread watching the message pump where all the user interface updates happen.

My Own Brute Force


Tag : python , By : potix2
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , So im trying to create my own type of brute force application. I know there are already versions out there on how to do it but i want help with a certain type of way that I'm doing it
from itertools import product
from string import ascii_lowercase, digits

possible_chars = ascii_lowercase + digits

for password_length in range(1, 9):  # up to 8 characters
    for chars in product(possible_chars, repeat=password_length):
        guess = "".join(chars)
        # test guess

Brute force using python


Tag : python , By : zac
Date : March 29 2020, 07:55 AM
should help you out I have an executable program that takes in a four digit pin number as a combination. I am supposed to crack the program using a python script. So far I got this. When I execute this, it prints only 9999. So I get "Wrong pin code: 9999". Please help. , Take care of identation:
import itertools
import os

numbers = '0123456789'
y = ''
for c in itertools.product(numbers, repeat=4):
    pin = y+''.join(c)
    print pin
    os.system("./xyz "+pin)

Brute force in Matlab


Tag : matlab , By : yogan
Date : March 29 2020, 07:55 AM
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