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New to PHP, trying to extract information from another website


New to PHP, trying to extract information from another website

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New to PHP, trying to extract information from another website
Tag : php , By : Edwin
Date : November 26 2020, 01:01 AM


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Web Api to extract information from website


Tag : javascript , By : Guyou
Date : March 29 2020, 07:55 AM
this one helps. You should have a look at YQL - it's a general-purpose service from Yahoo! that can do this kind of scraping really easily. Try this:
select * from html where url="google.com" and xpath='//title'

Extract information from a website


Tag : html , By : pad
Date : March 29 2020, 07:55 AM
wish helps you Basically use the developer tools in IE (f12) and find the element in question with ctrl + B you'd need to tweak the value for your providerNPI, but you can use something like this:
Private IE As Object
Private ieDoc As Object
Const Readystate_Complete As Long = 4

Sub GetData()
    Set IE = CreateObject("InternetExplorer.Application")
    IE.Visible = True
    IE.navigate "https://www.nctracks.nc.gov/publicPortal/provider/PractitionerSearch.action"
    ieBusyLoop
    Set ieDoc = IE.document
    ieDoc.getElementbyID("providerNPI").Value = "1234567890"
    IeClickID ("search")
    Set ieDoc = Nothing
End Sub
Private Sub IeClickID(ByVal ElId$)
    ieDoc.getElementbyID(ElId).Click
    OneSecDelay
    Call ieBusyLoop
End Sub
Private Sub OneSecDelay()
        waitTime = Now + TimeValue("00:00:01")
        Do Until Now >= waitTime: DoEvents: Loop
End Sub
Private Sub ieBusyLoop()
    Do While IE.busy: DoEvents: Loop
    Do Until IE.readystate = Readystate_Complete: DoEvents: Loop
End Sub

How to extract exact information from website using C#?


Tag : chash , By : Menno
Date : March 29 2020, 07:55 AM
I wish this helpful for you You can parse html document by using HtmlAgilityPack, simply download it from nuget. Here is a good tutorial about how to implement it.

How do I extract the information from the website?


Tag : python , By : SpittingCAML
Date : March 29 2020, 07:55 AM
hop of those help? Instead of clicking each vessel to open up the details, you can get the information you're searching for from the results page. This will get each vessel, pull the info you wanted and click to the next page if there are more vessels:
import selenium.webdriver as webdriver

url = "https://www.marinetraffic.com/en/data/?asset_type=vessels&columns=flag,shipname,photo,recognized_next_port,reported_eta,reported_destination,current_port,imo,ship_type,show_on_live_map,time_of_latest_position,lat_of_latest_position,lon_of_latest_position&ship_type_in|in|Cargo%20Vessels|ship_type_in=7"

browser = webdriver.Chrome('C:\Users\CSA\OneDrive - College Sainte-Anne\Programming\PYTHON\Learning\WS\chromedriver_win32 (1)\')
browser.get(url)
browser.implicitly_wait(5)

checking_for_vessels = True
vessel_count = 0

while checking_for_vessels:
    vessel_left_container = browser.find_element_by_class_name('ag-pinned-left-cols-container')
    vessels_left = vessel_left_container.find_elements_by_css_selector('div[role="row"]')

    vessel_right_container = browser.find_element_by_class_name("ag-body-container")
    vessels_right = vessel_right_container.find_elements_by_css_selector('div[role="row"]')

    for i in range(len(vessels_left)):
        vessel_count += 1
        vessel_country_list = vessels_left[i].find_elements_by_class_name('flag-icon')

        if len(vessel_country_list) == 0:
            vessel_country = 'Unknown'
        else:
            vessel_country = vessel_country_list[0].get_attribute('title')

        vessel_name = vessels_left[i].find_element_by_class_name('ag-cell-content-link').text
        vessel_imo = vessels_right[i].find_element_by_css_selector('[col-id="imo"] .ag-cell-content div').text

        print('Vessel #' + str(vessel_count) + ': ' + vessel_name + ', ' + vessel_country + ', ' + vessel_imo)

    pagination_container = browser.find_element_by_class_name('MuiTablePagination-actions')
    page_number = pagination_container.find_element_by_css_selector('input').get_attribute('value')
    max_page_number = pagination_container.find_element_by_class_name('MuiFormControl-root').get_attribute('max')

    if page_number == max_page_number:
        checking_for_vessels = False
    else:
        next_page_button = pagination_container.find_element_by_css_selector('button[title="Next page"]')
        next_page_button.click()

How to extract social information from a given website?


Tag : python , By : user170635
Date : March 29 2020, 07:55 AM
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