How to unload UIViewcontroller from memory?

How to unload UIViewcontroller from memory?

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How to unload UIViewcontroller from memory?
Tag : ios , By : Chris Tattum
Date : November 26 2020, 01:01 AM

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How do I unload a UIViewController from a UIScrollView?

Tag : iphone , By : Jakub Filak
Date : March 29 2020, 07:55 AM
This might help you I am using pretty much the same code to load my UIViewController (called LessonScrollView) into the UIScrollView. The method is called when in the scrollViewDidScroll method , Try this:
[controller.view removeFromSuperview];//to release the controller's view
[imageViewControllers replaceOjectAtIndex:page withObject:[NSNull null]];//to release the actual controller which should lead to it being dealocated

How to unload view of UIViewController

Tag : iphone , By : Patastroph
Date : March 29 2020, 07:55 AM
This might help you You don't. UIViewControllers don't get unloaded in low memory, just their views do.
This happens in didReceiveMemoryWarning on your own view controllers and gets called automatically when a low memory warning occurs.

Completely Unload UIViewController in ARC iOS App

Tag : ios , By : cheese_doodle
Date : March 29 2020, 07:55 AM
This might help you When done with it each time you need to release all references.
When you need to show it again, create and use a new instance. This is the only way to ensure viewDidLoad is called each time you need it.

How to load and unload a UIViewController from the window

Tag : ios , By : Hugo Hernan Buitrago
Date : March 29 2020, 07:55 AM
it should still fix some issue For me, is not a good way to load your view like this. It would be better to load a rootViewController in your AppDelegate and add your current view depending of your plist inside the RootViewController :
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
    RootViewController *rootViewController = [[RootViewController alloc] initWithNibName:@"RootViewController" bundle:nil];
    self.window.rootViewController = rootViewController;
    [self.window makeKeyAndVisible];
    return YES;
#pragma mark - View management
- (void)viewDidLoad
    [super viewDidLoad];

    NSDictionary *prefsDictionary = [prefsController readPrefs];

    NSLog(@"%@", prefsDictionary);

    NSString *projectListBoolString = [prefsDictionary objectForKey:@"ProjectListAvailable"];
    NSString *installsBoolString = [prefsDictionary objectForKey:@"InstallsAvailable"];
    NSString *finishinBoolString = [prefsDictionary objectForKey:@"FinishingAvailable"];

    if (([projectListBoolString isEqualToString:@"T"]) && ([installsBoolString isEqualToString:@"F"]) && ([finishinBoolString isEqualToString:@"F"])) {
        self.getProjectListViewController = [[GetProjectListViewController alloc] initWithNibName:@"GetProjectListViewController" bundle:nil];
        // Add View Controller
        [self.view addSubview:self.getProjectListViewController.view
    else if (([projectListBoolString isEqualToString:@"T"]) && ([installsBoolString isEqualToString:@"T"]) && ([finishinBoolString isEqualToString:@"T"])) {
        self.currentProjectListViewController = [[CurrentProjectListViewController alloc] initWithNibName:@"CurrentProjectListViewController" bundle:nil];
        // Add View Controller
        [self.view addSubview:self.currentProjectListViewController.view];
    else {
        self.viewController = [[ViewController alloc] initWithNibName:@"ViewController" bundle:nil];
        // Add View Controller
        [self.view addSubview:self.viewController.view];

How to unload self.view from UIViewController in Swift

Tag : ios , By : fayoh
Date : March 29 2020, 07:55 AM
Hope this helps According to View Controller Programming Guide, we can explicitly unload self.view from UIViewController by assigning nil to self.view. , setValue(nil, forKey:"view") seems to work:
override func didReceiveMemoryWarning() {
    if self.view.window == nil {
        self.setValue(nil, forKey: "view")
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