wish help you to fix your issue I suggest you use exactly 1 interrupt, and organize your timers in either a queue (for few times, e.g. <50) or in a heap, which is quite a quick tree which, at any time, gives you access to the smallest element, that is, the element with the next Timer to be handled. Thus you have one interrupt, one handler, and many Timers with associated functions that will be called by that single handler.
How to transmit a register value to parallel port using DOS interrupt?
wish helps you Yes, you can get the parameter values by dereferencing the user esp. Just as with any void *, you must cast it to a suitable pointer type before dereferencing it or indexing it. In this case, uint32_t * would be appropriate, so you would use
will help you The key thing to understand is that the USART has 2 separate hardware registers that are used in the data transmission: UDRn and the Transmit Shift Register, which I'll just call TSR from now on. When you write data to UDRn, assuming no tx is in progress, it'll get moved to the TSR immediately and the UDRE irq fires to tell you that the UDRn register is "empty". Note that at this point the transmission has just started, but the point is that you can already write the next byte to UDRn.
Is it possible in linux to register a interrupt handler from any user-space program?