Match a regular expression, then remove a subset of that regular expression
Date : March 29 2020, 07:55 AM
around this issue replace can take a function: var fraction;
var street_address = "1234 1/2 Old Town Alexandria".replace(/^\d*\s+(1[/]\d)\s+/i, function (match, capture) {
fraction = capture.trim();
return match.replace(capture,'')
});
fraction; // 1/2
street_address; // 1234 Old Town Alexndria
|
Tag : php , By : dyarborough
Date : March 29 2020, 07:55 AM
I wish this help you Yes, since .* matches everything (including the tags), you're matching too much. If you restrict your regex not to match across tag boundaries by preventing it from matching angle brackets, you get the desired result: $test ='<number>1<number>2</number>3</number>';
$i=0;
$find[$i]="%<number>([^<>]*)</number>%is";
$replace[$i]="5";
$i++;
$find[$i]="%<number>([^<>]*)</number>%is";
$replace[$i]="$1";
|
How to match expression of SQL IN operator contain nested braces using regular expression?
Tag : regex , By : nickthecook
Date : March 29 2020, 07:55 AM
it helps some times I want to match expression of IN operator in SQL statement. First, I use , You can use: (?sUi)\s+in\s*\(((?:[^)']+|'[^']*')*)\)
(?sUi)\s+in\s*\(((?:[^)']+|'(?:[^']|'')*')*)\)
|
regular expression to completely remove html attribute from element
Tag : regex , By : GunnarHafdal
Date : March 29 2020, 07:55 AM
I wish this helpful for you Try this Regex... Please see here for more information on this Regex. <?(title)="[^"]*"
|
php remove element from array using regular expression
Tag : php , By : ponchopilate
Date : March 29 2020, 07:55 AM
it should still fix some issue You can use array_filter to strip out the entries in your array that start with DHL, using the regex ^DHL to see if the entry starts with DHL: $array = array(
0 => 'DHL - 4857998880',
1 => 'DHL - 4858005666',
2 => 'COA - 485344322'
);
$array = array_filter($array, function ($v) { return !preg_match('/^DHL/', $v); });
print_r($array);
Array (
[2] => COA - 485344322
)
|