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How to remove year from datetime object?


How to remove year from datetime object?

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How to remove year from datetime object?
Tag : chash , By : ck1
Date : November 26 2020, 01:01 AM


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python pandas extract year from datetime --- df['year'] = df['date'].year is not working


Tag : python , By : jaset
Date : March 29 2020, 07:55 AM
With these it helps If you're running a recent-ish version of pandas then you can use the datetime attribute dt to access the datetime components:
In [6]:

df['date'] = pd.to_datetime(df['date'])
df['year'], df['month'] = df['date'].dt.year, df['date'].dt.month
df
Out[6]:
        date  Count  year  month
0 2010-06-30    525  2010      6
1 2010-07-30    136  2010      7
2 2010-08-31    125  2010      8
3 2010-09-30     84  2010      9
4 2010-10-29   4469  2010     10
In [18]:

df['date'] = pd.to_datetime(df['date'])
df['year'], df['month'] = df['date'].apply(lambda x: x.year), df['date'].apply(lambda x: x.month)
df
Out[18]:
        date  Count  year  month
0 2010-06-30    525  2010      6
1 2010-07-30    136  2010      7
2 2010-08-31    125  2010      8
3 2010-09-30     84  2010      9
4 2010-10-29   4469  2010     10
In [20]:

t="""date   Count
6/30/2010   525
7/30/2010   136
8/31/2010   125
9/30/2010   84
10/29/2010  4469"""
df = pd.read_csv(io.StringIO(t), sep='\s+', parse_dates=[0])
df.info()
<class 'pandas.core.frame.DataFrame'>
Int64Index: 5 entries, 0 to 4
Data columns (total 2 columns):
date     5 non-null datetime64[ns]
Count    5 non-null int64
dtypes: datetime64[ns](1), int64(1)
memory usage: 120.0 bytes

Set the year in a DateTime object


Tag : chash , By : jumpingmattflash
Date : March 29 2020, 07:55 AM
it fixes the issue You just need to create a new DateTime since DateTime is an immutable struct:
DateTime newDt = new DateTime(2099, dt.Month, dt.Day);
public static DateTime ChangeYear(this DateTime dt, int newYear)
{
    return dt.AddYears(newYear - dt.Year);
}
DateTime dt = new DateTime(2016, 2, 29);
DateTime newDt = dt.ChangeYear(2099); 

DateTime object How to change the year to be the current year


Tag : php , By : pttr
Date : March 29 2020, 07:55 AM
To fix the issue you can do You can either use modify() to increment/decrement to current year or use setDate() like this:
$dob->setDate((int) date("Y"), (int)$dob->format('m'), (int)$dob->format('d'));

How to access last year values to compare year on year ? datetime index


Tag : python , By : user181445
Date : March 29 2020, 07:55 AM
wish of those help IIUC, you need this.
This works only when you have date time as index. What we are doing here is grouping by day & month using the datetime value & even if the dates are between leap-year & a normal-year, this should work.
performance_df['LY_Revenue'] = performance_df.groupby([performance_df.index.month,performance_df.index.day])['Revenue'].shift()
print(performance_df)
                Revenue     LY_Revenue
Date        
2018-01-01  25891.846787    NaN
2018-01-02  25851.615541    NaN
2018-01-03  25037.711900    NaN
2018-01-04  26715.764965    NaN
2018-01-05  23988.356950    NaN
2018-01-06  19029.057983    NaN
2018-01-07  16935.481705    NaN
2018-01-08  22756.072913    NaN
2018-01-09  30385.672829    NaN
2018-01-10  32970.132175    NaN
2018-01-11  31089.167075    NaN
2018-01-12  24262.972415    NaN
2018-01-13  18261.273832    NaN
2018-01-14  18304.754084    NaN
2018-01-15  26297.835665    NaN
2018-01-16  32619.669405    NaN
2018-01-17  35565.262225    NaN
2018-01-18  33229.971940    NaN
2018-01-19  25405.647136    NaN
2018-01-20  19980.890375    NaN
2018-01-21  20487.553161    NaN
2018-01-22  29709.032322    NaN
2018-01-23  38164.493648    NaN
2018-01-24  39050.801147    NaN
2018-01-25  36612.554433    NaN
2018-01-26  28169.782524    NaN
2018-01-27  22086.641618    NaN
2018-01-28  21631.662706    NaN
2018-01-29  28419.945290    NaN
2018-01-30  35644.617364    NaN
...     ...     ...
2019-12-02  2973.892113     28289.697207
2019-12-03  2674.316864     34737.317368
2019-12-04  2460.238549     40574.910348
2019-12-05  2800.034200     40556.066887
2019-12-06  3195.262337     39927.322507
2019-12-07  3107.693557     34634.748383
2019-12-08  2961.140812     27666.467364
2019-12-09  2340.478044     27774.363832
2019-12-10  1931.373925     33950.846875
2019-12-11  1847.123639     39518.061312
2019-12-12  2179.325333     39587.568701
2019-12-13  2438.035383     38832.660311
2019-12-14  2379.865127     32258.462222
2019-12-15  2255.598970     23343.008315
2019-12-16  1870.926018     23914.895775
2019-12-17  1620.608382     28173.094175
2019-12-18  1511.311007     30306.555827
2019-12-19  1685.967616     28284.310392
2019-12-20  2099.849763     24228.754426
2019-12-21  2430.507619     20495.999365
2019-12-22  2701.975519     19302.936445
2019-12-23  2997.630051     21391.090777
2019-12-24  2977.347247     21072.220129
2019-12-25  2893.576704     19770.681250
2019-12-26  3207.467022     22751.205447
2019-12-27  3539.618050     25744.075480
2019-12-28  3534.997476     27119.697589
2019-12-29  3527.721147     28894.626077
2019-12-30  3489.915430     30321.364425
2019-12-31  3287.543337     29665.558703

How to get day of year, week of year from a DateTime Dart object


Tag : development , By : avi
Date : March 29 2020, 07:55 AM
will be helpful for those in need I need to get day of year (day1 is 1rst of january), week of year, and month of year from a dart DateTime object. , Day of year
final date = someDate;
final diff = now.difference(new DateTime(date.year, 1, 1, 0, 0));
final diffInDays = diff.inDays;
final date = someDate;
final startOfYear = new DateTime(date.year, 1, 1, 0, 0);
final firstMonday = startOfYear.weekday;
final daysInFirstWeek = 8 - firstMonday;
final diff = date.difference(startOfYear);
var weeks = ((diff.inDays - daysInFirstWeek) / 7).ceil();
// It might differ how you want to treat the first week
if(daysInFirstWeek > 3) {
  weeks += 1;
}
final monthOfYear = new DateTime.now().month;
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