Django - Class Based Generic View - "No URL to redirect to"
Date : March 29 2020, 07:55 AM
it fixes the issue I'm using the generic CreateView like: , Have you tried passing in success_url? e.g. CreateView.as_view(model=myModel, success_url="/success/")
CreateView.as_view(model=myModel, success_url=reverse('success-url'))
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Django: model object "has no attribute '_meta'" in class based view
Date : March 29 2020, 07:55 AM
wish helps you Hi Stackoverflow people, , Change: class Project(models.Manager)
class Project(models.Model)
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What is equivalent of "direct to template" in class based view in django
Tag : django , By : user181345
Date : March 29 2020, 07:55 AM
I wish this helpful for you That would be the TemplateView, and you use it like: from django.conf.urls import patterns, url
from django.views.generic.base import TemplateView
urlpatterns = patterns('',
url(r'^foo/$', TemplateView.as_view(template_name='foo_index.html')),
)
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Django: can "double" 'render_to_response' be unified into only one view?
Tag : html , By : acolomba
Date : March 29 2020, 07:55 AM
With these it helps Yes, you can use the single view. Add the default None value for the id (or pk) argument: def show_elementi(request, pk=None):
elementimenu = ElementiTab.objects.all()
detail = get_object_or_404(ElementiTab, pk=pk) if pk else None
return render(request, 'homepage/prova.html',
{'elementimenu': elementimenu, 'detail': detail})
url(r'^homepage/prova/$', views.show_elementi),
url(r'^show_detail/(?P<pk>\d+)/$', views.show_elementi),
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Django GET ?q="parameter" in get_queryset Class Based View
Date : March 29 2020, 07:55 AM
should help you out How do I access the "parameter" word in the url: , It should be self.request.GET['q'].
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