how can i escape a group of special characters in java in one method?
Tag : java , By : user121405
Date : March 29 2020, 07:55 AM
|
String's replaceAll() method and escape characters
Date : March 29 2020, 07:55 AM
like below fixes the issue When replacing characters using regular expressions, you're allowed to use backreferences, such as \1 to replace a using a grouping within the match. This, however, means that the backslash is a special character, so if you actually want to use a backslash it needs to be escaped.
|
replaceAll type method that preserves special characters
Tag : java , By : Justin Bowers
Date : March 29 2020, 07:55 AM
it should still fix some issue Why not use String#replace method instead of replaceAll. replaceAll uses regex but replace doesn't use regex in replacement string.
|
Java replaceAll escape characters into double escape
Date : March 29 2020, 07:55 AM
Hope this helps I have a string value which received from input field. , You should do: string = string.replaceAll("\\\\", "\\\\\\\\");
|
Java use replaceAll with Escape Characters String
Tag : java , By : Marcos de Carvalho
Date : March 29 2020, 07:55 AM
I hope this helps . Don't use replaceAll(), which does a regex search. Instead use replace(), which uses plain-text search. getXML = getXML.replace(headerXMLString, "");
getXML = getXML("^<?xml.*?\\?>", "");
|