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Uploading multiple files in a single request using python requests module


Uploading multiple files in a single request using python requests module

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Uploading multiple files in a single request using python requests module
Tag : development , By : fayoh
Date : November 25 2020, 07:06 PM


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Box API v2 uploading multiple files per single request is limited to 20


Tag : development , By : Matt Croydon
Date : March 29 2020, 07:55 AM
Any of those help We just looked into this, and it is indeed a bug with the v2 API. We are working on resolving it, and I will update here when it has been fixed.

Uploading multiple files via single form field via Python CGI


Tag : python , By : fstender
Date : March 29 2020, 07:55 AM
around this issue Remove for file in form. The error implies that form['file'] is a list.
Add to html form: method=post enctype=multipart/form-data.
import shutil

if 'file' in form:
   filefield = form['file']
   if not isinstance(filefield, list):
      filefield = [filefield]

   for fileitem in filefield:
       if fileitem.filename:
          fn = secure_filename(fileitem.filename)
          # save file
          with open('/var/www/domain.com/files/' + fn, 'wb') as f:
              shutil.copyfileobj(fileitem.file, f)

Uploading files using Python requests module


Tag : python , By : anon
Date : March 29 2020, 07:55 AM
it fixes the issue You aren't sending the contents of the file anywhere. You're just sending a reference to a file that doesn't exist anywhere that the server can see.
As the docs for SOAP references to attachments explains, the way you do this is to send a MIME-multipart message. If you're using the CID reference mechanism, that cid isn't some arbitrary string, it has to match the Content-ID header of a message in the MIME envelope.
with open('FUZZY.csv', 'rb') as f:
    files = {'file': f}
    r = requests.post(target_url,
                      data=xml, headers=headers, auth=('3user1',''), 
                      files=files)

How to send multiple files using python's requests module and customize the header for each file?


Tag : python , By : 66.
Date : March 29 2020, 07:55 AM
To fix this issue This is what a multipart HTTP request looks like, all the headers go at the beginning except the content-type and content-disposition for the multipart contents (they describe the content) and they only apply if the top level content-type is multipart/form-data:
POST /test HTTP/1.1
Host: host
User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/41.0.2228.0 Safari/537.36
Accept: text/html
Accept-Language: en-us
Accept-Charset: utf-8
Keep-Alive: 300
Connection: keep-alive
Content-Type: multipart/form-data; boundary=---------------------------3141592654
Content-Length: 111

-----------------------------3141592654
Content-Disposition: form-data; name="image"; filename="foo.png"
Content-Type: image/png
[img-data]
-----------------------------3141592654
Content-Disposition: form-data; name="image"; filename="bar.png"
Content-Type: image/png
[img-data]

How to aiohttp request post files list python requests module?


Tag : python , By : nseibert
Date : March 29 2020, 07:55 AM
it helps some times According to POST a Multipart-Encoded File - Client Quickstart - aiohttp documentation, you need to specify the file as data dictionary (value should be a file-like object):
import asyncio
import aiohttp


async def main():
    url = 'http://httpbin.org/anything'
    with open('t.py', 'rb') as f:
        async with aiohttp.ClientSession() as session:
            async with session.post(url, data={'key': f}) as response:
                return await response.text()


text = asyncio.run(main())  # Assuming you're using python 3.7+
print(text)
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