Use jQuery to find out how many list items are in an unordered list
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I am creating a tabbed content interface. The content panels are an unordered list created using a server-side script. I want to add tabs via jQuery to control the panels. The only requirement for the jQuery plugin to work is to have the same amount of panels as tabs (the number of panels isn't always consistent). I need to query how many list items are in my ul.panels and store it in a variable, so I can create a loop with that variable to append my list items in ul.tabs. var count = $("ul.panels li").size();
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Find text in unordered list and click on link within that list item
Tag : ruby , By : Mariocki
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I guess you are saying that you don't know the link href ahead of time? Assuming you have opened the page in question using a Watir::Browser variable called browser: browser.li(:text, /Apple/).link(:text, 'Login to this account').click
browser.link(:href, 'http://samplegrocerystore.com/tehnc34').click
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Why is not a child unordered list inside of a parent unordered list item occupying the whole space available as of it's
Tag : html , By : Vasiliy
Date : March 29 2020, 07:55 AM
hop of those help? See the updated jsfiddle: ul#navmenu li ul.sub1 {
width: 100%;
}
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How can I find childs of an unordered list
Date : March 29 2020, 07:55 AM
like below fixes the issue Your code seems overly complicated to achieve the desired result. You can use the jQuery hover function, to define mouseenter and mouseleave event handlers. https://api.jquery.com/hover/$(".cl li").hover(function(){
$(this).find('.cl_extra').slideDown();
}, function(){
$(this).find('.cl_extra').slideUp();
});
/* Stand
***************************/
body {
width: 960px;
margin: 0 auto;
font-family: 'PT Sans Narrow', sans-serif;
color: #000;
}
/***************************/
ul.cl {
list-style-type: none;
padding: 0;
}
ul.cl li {
width: 25%;
display: inline-block;
padding: 10px 20px;
border-radius: 10px 10px 0 0;
background: #0EA4DB;
color: #fff;
box-shadow: 10px 15px 25px grey;
vertical-align: top;
}
ul.cl li h1 {
font-size: 40px;
margin: 5px 0 0 0;
}
ul.cl li h2 {
font-size: 12px;
margin-bottom: 10px;
}
ul.cl li a {
color: #fff;
text-decoration: none;
}
ul.cl li span {
color: #E8B928;
}
.cl_extra {
display: none;
}
<body>
<ul class="cl">
<li>
<a href="#"><h1>Such News Much Wow</h1>
<h2>Posted: 11-3-2017 by: <span>Dodge</span></h2></a>
<p class="cl_extra">Lorem ipsum dolor sit amet, consectetur adipiscing elit. Curabitur eleifend elit dapibus aliquet euismod. Pellentesque feugiat placerat orci, a pretium nisi rhoncus id. Proin accumsan purus lacus, vitae dapibus turpis interdum quis. Mauris nulla libero, tempor a quam vitae, volutpat dapibus enim. Nunc tempor elementum leo, quis ultricies mauris pretium at. Pellentesque augue enim, efficitur quis elit vitae, dapibus venenatis neque. Sed vel turpis libero.</p>
</li>
<li>
<a href="#"><h1>Such CSS Much JS</h1>
<h2>Posted: 11-3-2017 by: <span>Dodge</span></h2></a>
<p class="cl_extra">Lorem ipsum dolor sit amet, consectetur adipiscing elit. Curabitur eleifend elit dapibus aliquet euismod. Pellentesque feugiat placerat orci, a pretium nisi rhoncus id. Proin accumsan purus lacus, vitae dapibus turpis interdum quis. Mauris nulla libero, tempor a quam vitae, volutpat dapibus enim. Nunc tempor elementum leo, quis ultricies mauris pretium at. Pellentesque augue enim, efficitur quis elit vitae, dapibus venenatis neque. Sed vel turpis libero.</p>
</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
</body>
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How to understand the complexity of medians of medians algorithm?
Date : March 29 2020, 07:55 AM
To fix this issue After dividing the list into n/5 groups of 5, and finding the median of medians p, you need to determine a worst case for how many elements you still have to look for the true median in.
Consider how many elements of the list must be smaller than p (or equal to, which in the simpler list of distinct elements case is only p)
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