Printing numbers column by column

Printing numbers column by column

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Printing numbers column by column
Tag : cpp , By : Anonymous
Date : November 25 2020, 07:06 PM

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read numbers from files in columns, one column whole numbers, other column numbers with decimals

Tag : cpp , By : Liviu Aileni
Date : March 29 2020, 07:55 AM
Any of those help The best way would be to get each separately. If it is from a file then you can do this:
int itemnum;
double price;

inputFile >> itemNum >> price; //If the columns are ItemNumber then Price
inputFile >> price >> itemnum; //If the columns are the other way around
#include <fstream>
#include <iostream>

int main()
    int input1;
    double input2;

    //Open file
    std::ifstream inFile;
    inFile.open("myFile.txt"); //or whatever the file name is

        //Get input
        inFile >> input1 >> input2;

        //Print input
        std::cout << input1 << " " << input2 << " ";

    //Close file

    return 0;

add a new column of numbers to whitespace delimited data based on another column of numbers using Bash utilities

Tag : bash , By : Navin
Date : March 29 2020, 07:55 AM
will help you I want to perform a simple calculation on each number in a column of whitespace delimited data using Bash utilities such as cut and bc. The data may look like something such as the following: , try this short line:
awk '$2=$2" "sprintf("%.3f",$2)' file
kent$  echo "string 0.998663 string string string
string 0.998592 string string string
string 0.999096 string string string"|awk '$2=$2" "sprintf("%.3f",$2)'
string 0.998663 0.999 string string string
string 0.998592 0.999 string string string
string 0.999096 0.999 string string string

Column A numbers matched with Column B numbers that are assigned to Column C =column D?

Tag : excel , By : ezzze
Date : March 29 2020, 07:55 AM
seems to work fine It is hard to guess what your data looks like, so assuming your data looks as below:

How to fill a column with the numbers of third column associated to the strings of fourth column in Unix environment?

Tag : bash , By : Rohii
Date : March 29 2020, 07:55 AM
it helps some times I have a TAB file something like , Try this:
awk -F'\t' '
FNR == NR {
        arr[$4] = ($1) ? $1 : $3;
FNR != NR {
        printf "%d", arr[$4];
}' input.txt input.txt

Generating a Column of Timestamps from a Column of Numbers Returns NAs in the Middle and End of the Column

Tag : r , By : msugar
Date : March 29 2020, 07:55 AM
around this issue Have you thought about using the seq.POSIXt function in R's base library?
The function takes the following: seq.POSIXt(from, to, by, length.out = NULL, along.with = NULL, ...)
fromDate <- as.POSIXct('2018-03-22')
toDate <- as.POSIXct('2018-03-23')

df<-as.data.table(seq.POSIXt(fromDate, toDate, by = '3 min'))
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