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More Return Statements vs. More Indentation


More Return Statements vs. More Indentation

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More Return Statements vs. More Indentation
Tag : c , By : Angel Paunchev
Date : November 25 2020, 07:06 PM


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Formatting/indentation for using statements (C#)


Tag : chash , By : tanminivan
Date : March 29 2020, 07:55 AM
help you fix your problem As others have said, always use braces. However, there's one idiom which somewhat goes against this and uses the "non-indentation":
using (Resource1 res1 = new Resource1())
using (Resource2 res2 = new Resource2())
using (Resource3 res3 = new Resource3())
{
    // Do stuff with res1, res2 and res3
}

Why doesn't the different indentation of two functions' return statements produce different results?


Tag : python , By : CrimsonGore
Date : March 29 2020, 07:55 AM
With these it helps Neither of these does what you want. With the first, only the first two items will be compared, because you return in the first iteration of the loop regardless of whether the first two items are in order (although you return different results in these cases). The for loop doesn't really do anything. With the second, items will continue being compared only if they are out of order, because you return from the function the first time you see pair that is in order.
What you want is to return False immediately when items are out of order (since once you have found a pair of items out of order, you know the list is not sorted and don't need to check any further) and keep going only when pairs are in order, returning True only after you have inspected all items. Like this:
def is_sorted(t):
    for i in range(len(t) - 1):
        if t[i] > t[i + 1]:
            return False
    return True
def is_sorted(t):
    return all(t[i] <= t[i + 1] for i in range(len(t) - 1))

Indentation with Let Statements


Tag : haskell , By : orneka
Date : November 22 2020, 10:31 AM
seems to work fine I'm afraid I'm tapped out on understanding this and the let block in general. , The in has to line up with the let or be on the same line:
| otherwise = let (x, xrst) = break tf xs
              in [[x], splitWith tf (tail xrst)]
| otherwise =
    let (x, xrst) = break tf xs
    in [[x], splitWith tf (tail xrst)]

Indentation of preprocessor statements in C


Tag : c , By : Raghaw
Date : March 29 2020, 07:55 AM
around this issue The short answer is: auto-indentation on editors follow established language guidelines, and what you are trying to do is not considered 'good practice' and thus has not been implemented in any editor (that I've seen at least).
Longer answer: The C language does not have any indentation rules, so any indentation done is by established practice. And different people have different opinions on what their ideal of established practice is. Specifically for preprocessor conditionals, I have never seen anyone use any additional depth - and IMO that would be bad practice as it would get terribly confusing when intermixed with the language conditionals (i.e. if (code)) Take a look at these 2 basic examples:
    if (conditional1)
        action1();
#if compileoption1
        else if (conditional2)
            action2();
#else
        action3();
#endif
#if compileoption1
    if (conditional1)
#endif
    action1();

Multiple If Statements Indentation Error?


Tag : vba , By : rhyhann
Date : March 29 2020, 07:55 AM
this will help The problem appears to be in your first block.
Your code (with added indentations to show the flow):
If Awarding = "First Half All Credits in One Half" Or Awarding = "Second Half Only" Then
     If LEU.Value <> "" And PLEU < CalcElig Then
         Payment1.Value = PLEU
         If PAmtUnused < CalcElig Then
            'This will write over Payment1.Value if both If conditions are satisfied.
             Payment1.Value = PAmtUnused
         Else: Payment1.Value = Payment1.Value = Round(CLng(PSchAward) *      PTotalAyWeeks / PMinAyWeeks / 2, 0)
      'The else condition will write over Payment1.Value if the second If condition is not satisfied.
         End If
'Payment1.Value is NEVER set if the first IF statement evaluates to FALSE,
' and it is written over if the first IF statement evaluates to TRUE!!
         PPayment1 = Payment1.Value
         PPayment2 = 0
         TotalPayment = PPayment1 + PPayment2
     End If
End If
If Awarding = "First Half All Credits in One Half" Or Awarding = "Second Half Only" Then
    If LEU.Value <> "" And PLEU < CalcElig Then
        Payment1.Value = PLEU
    ElseIf PAmtUnused < CalcElig Then
        Payment1.Value = PAmtUnused
    Else: Payment1.Value = Payment1.Value = Round(CLng(PSchAward) *      PTotalAyWeeks / PMinAyWeeks / 2, 0)
    End If

    PPayment1 = Payment1.Value
    PPayment2 = 0
    TotalPayment = PPayment1 + PPayment2

End If
Else: Payment1.Value = Payment1.Value = Round(CLng(PSchAward) *      PTotalAyWeeks / PMinAyWeeks / 2, 0)
 Else: Payment1.Value = (Payment1.Value = Round(CLng(PSchAward) *      PTotalAyWeeks / PMinAyWeeks / 2, 0))
Else: Payment1.Value = Round(CLng(PSchAward) *      PTotalAyWeeks / PMinAyWeeks / 2, 0)
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