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Is there a macro-based adapter to make a functor from a class?


Is there a macro-based adapter to make a functor from a class?

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Is there a macro-based adapter to make a functor from a class?
Tag : cpp , By : rajiv
Date : November 25 2020, 07:06 PM


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C++ functor to output iterator adapter


Tag : cpp , By : Rit Li
Date : March 29 2020, 07:55 AM
Does that help How about boost::function_output_iterator?

Defining a class with functor-ish and non-functor-ish functions


Tag : haskell , By : simonth
Date : March 29 2020, 07:55 AM
I hope this helps you . One possibility is to encode the "Container" type using another associated type.
import qualified Data.Map.Lazy as M

class MyMap m where
  type Key m
  type Value m
  type Container m :: * -> *
  keys :: m -> [Key m]
  elems :: m -> [Value m]
  mapify :: (a -> b) -> Container m a -> Container m b

instance MyMap (M.Map k v) where
  type Key (M.Map k v) = k
  type Value (M.Map k v) = v
  type Container (M.Map k v) = M.Map k
  keys = M.keys
  elems = M.elems
  mapify = M.map
class MyMap m where
  type Key m
  type Value m
  type Container m :: * -> *
  keys :: m -> [Key m]
  elems :: m -> [Value m]
  -- mapify :: (a -> b) -> Container m a -> Container m b

  -- Make sure the type-checker knows that m2 is just the container of m with
  -- a different value
  mapify :: (MyMap m2, m2 ~ Container m (Value m2)) => (Value m -> Value m2) -> m -> m2


instance MyMap (M.Map k v) where
  type Key (M.Map k v) = k
  type Value (M.Map k v) = v
  type Container (M.Map k v) = M.Map k
  keys = M.keys
  elems = M.elems
  mapify = M.map

doSomething
  :: (MyMap m1, MyMap m2, m2 ~ Container m1 (Value m2)) =>
     (Value m1 -> Value m2) -> m1 -> m2
doSomething f m = mapify f m

Is it more efficient to make an functor with no members a class member object or a stack object?


Tag : cpp , By : Nickolas
Date : March 29 2020, 07:55 AM
should help you out For an empty object, just create it in the stack. Adding the functor to your type as a member will make all of your objects larger. Adding it as a base (to make use of the empty base optimization), will yield a weird design in which your type implements operator()(const MyData&) for no reason. Even if you make it private the operator will be there.
Since the type has no members, there is no cache locality issues, as no data to be accessed. The main use of a stateless functor is to allow the compiler to inline the call to the function (compared with a free function with the same name)

Why can I not make a (Functor f) => ConcreteType -> f String into an instance Functor ((->) ConcreteType)?


Tag : haskell , By : user176445
Date : March 29 2020, 07:55 AM
Hope this helps You've overspecialized.
The definition of a functor is as follows:
class Functor f where
    fmap :: (a -> b) -> f a -> f b

How to Make JTable in adapter class and calling it in main class


Tag : java , By : user103892
Date : March 29 2020, 07:55 AM
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