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Python Syntax Error, 'break' is outside the loop


Python Syntax Error, 'break' is outside the loop

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Python Syntax Error, 'break' is outside the loop
Tag : python , By : John Tate
Date : November 25 2020, 07:06 PM


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How to break the line in a python if statement without a syntax error?


Tag : python , By : Simon Capewell
Date : March 29 2020, 07:55 AM
I wish did fix the issue. In general when you want to split up an expression onto multiple lines, use parentheses:
if (not "string1" in item 
    and not "string2" in item 
    and not "string3" in item 
    and not "string4" in item):
    doSomething(item)
if not any(s in item for s in ("string1", "string2", "string3", "string4")):
    doSomething(item)

using break in an inline if statement in a loop causes a syntax error


Tag : python , By : stu73
Date : March 29 2020, 07:55 AM
may help you . This is called conditional expression and the Grammer for that is defined like this
conditional_expression ::=  or_test ["if" or_test "else" expression]
or_test  ::=  and_test | or_test "or" and_test
and_test ::=  not_test | and_test "and" not_test
not_test ::=  comparison | "not" not_test
comparison    ::=  or_expr ( comp_operator or_expr )*
comp_operator ::=  "<" | ">" | "==" | ">=" | "<=" | "!="
                   | "is" ["not"] | ["not"] "in"
or_expr  ::=  xor_expr | or_expr "|" xor_expr
xor_expr ::=  and_expr | xor_expr "^" and_expr
and_expr ::=  shift_expr | and_expr "&" shift_expr
shift_expr ::=  a_expr | shift_expr ( "<<" | ">>" ) a_expr
a_expr ::=  m_expr | a_expr "+" m_expr | a_expr "-" m_expr
m_expr ::=  u_expr | m_expr "*" u_expr | m_expr "//" u_expr | m_expr "/" u_expr
            | m_expr "%" u_expr
u_expr ::=  power | "-" u_expr | "+" u_expr | "~" u_expr
power ::=  primary ["**" u_expr]
primary ::=  atom | attributeref | subscription | slicing | call

Syntax Error 'break outside loop'


Tag : python , By : mtnmuncher
Date : March 29 2020, 07:55 AM
I wish this help you Essentially, I'm trying to create a main function that can take input, and use that list of input to calculate the median, mode, and mean by using another function. I'm a novice coder (taking my first class) so any help that can point me in the right direction while still helping me learn will be greatly appreciated. , Personal preference, but I would change your if statements to
if 'stop' not in addons:
    data.append(yourlist)
elif not all(isinstance(number, float) for number in addons):
    print("Bad input, try again")

While loop not accepting the break function, classed as syntax error?


Tag : python , By : Trevor Cortez
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Am in the middle of a project for school and am trying to use a while True loop in order to get a specific answer from an input. I tried the following and IDLE labels break as a syntax error.
while True:
    RequestTea = input("What tea would you like? English Breakfast, Green Tea or Earl Grey? ").lower()
    if RequestTea.lower() not in ('earl grey','english breakfast','green tea'):
        print("Not an appropriate choice.")
    else:
        break

Why got syntax error 'break' outside loop?


Tag : python , By : redha
Date : March 29 2020, 07:55 AM
should help you out Check the last two line of your code. Where the break is out of any loop.
Put it in the specific loop, if you need it, otherwise remove it.
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