Inquiry about writing a Char via ByteBuffer

Inquiry about writing a Char via ByteBuffer

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Inquiry about writing a Char via ByteBuffer
Tag : java , By : meodudang
Date : November 25 2020, 01:01 AM

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Fast ByteBuffer to CharBuffer or char[]

Tag : java , By : Eugenio
Date : March 29 2020, 07:55 AM
To fix the issue you can do So, what you want is to convert using the encoding ISO-8859-1.
I don't claim anything about efficiency, but at least it is quite short to write:
CharBuffer result = Charset.forName("ISO-8859-1").decode(byteBuffer);
ByteBuffer result = Charset.forName("ISO-8859-1").encode(charBuffer);
CharBuffer result = StandardCharsets.ISO_8859_1.decode(byteBuffer);
ByteBuffer result = StandardCharsets.ISO_8859_1.encode(charBuffer);

Inquiry about writing plugins for Autodesk Maya

Tag : cpp , By : vferman
Date : March 29 2020, 07:55 AM
will be helpful for those in need
Yes, for plugins you need a id range if you wish to share them. Its not really easy tough. Maya has a really deep hardcore philosophy, if you try to use Maya the wrong way it will totally freak at you. After that point everything you do will be a serious uphill battle.

Is it possible that in Java 7 (byte) ((char) ByteBuffer.get(X)) != ByteBuffer.get(X)?

Tag : java , By : perl
Date : March 29 2020, 07:55 AM
may help you . No, the behavior has not changed from 1.6 to 1.7 -- or, for that matter, from 1.0 to 1.7.
When you execute this line of code:
char c = (char) buffer.get();

Why i get extra char '^@' when writing char to a big file using byteBuffer in Java

Tag : java , By : user158220
Date : March 29 2020, 07:55 AM
hope this fix your issue I am trying to write chars to a file, not sure why it writes ^@
// 1 char =2 bytes
final byte[] array = theString.getBytes("UTF-8");

Is put-ing to a ByteBuffer then writing it to a file more efficient than writing the individual field

Tag : java , By : Maplye
Date : March 29 2020, 07:55 AM
This might help you As you are doing file I/O, you should bear in mind that the I/O operations are likely to be very much slower than any work done by the CPU in your output code. To a first approximation, the cost of I/O is an amount proportional to the amount of data you are writing, plus a fixed cost for each operating system call made to do the I/O.
So in your case you want to minimise the number of operating system calls to do the writing. This is done by buffering data in the application, so the application performs few put larger operating system calls.
 OutputStream bo = new BufferedOutputStream(new FileOutputStream(checking));
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