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Is there a key for the default namespace when creating dictionary for use with xml.etree.ElementTree.findall() in Python


Is there a key for the default namespace when creating dictionary for use with xml.etree.ElementTree.findall() in Python

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Is there a key for the default namespace when creating dictionary for use with xml.etree.ElementTree.findall() in Python
Tag : python , By : PatrickSimonHenk
Date : November 25 2020, 01:01 AM


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What's difference between findall() and iterfind() of xml.etree.ElementTree


Tag : python , By : user106284
Date : March 29 2020, 07:55 AM
should help you out I write a program using just like below , Like indicated in the docs -
>>> root = ET.fromstring("<a><b>c</b></a>")
>>> root.findall("./b")
[<Element 'b' at 0x02048C90>]
>>> lst = root.findall("./b")
>>> lst[0]
<Element 'b' at 0x02048C90>
In [1]: import xml.etree.ElementTree as ET

In [2]: x = ET.fromstring('<a><b>c</b><b>d</b><b>e</b></a>')

In [3]: def foo(root):
   ...:     d = root.findall('./b')
   ...:     for  y in d:
   ...:         pass
   ...: 

In [4]: def foo1(root):
   ...:     d = root.iterfind('./b')
   ...:     for y in d:
   ...:         pass
   ...: 

In [5]: %timeit foo(x)
100000 loops, best of 3: 9.24 µs per loop

In [6]: %timeit foo1(x)
100000 loops, best of 3: 6.65 µs per loop

In [7]: def foo2(root):
   ...:     return root.findall('./b')
   ...: 

In [8]: def foo3(root):
   ...:     return list(root.iterfind('./b'))
   ...: 

In [9]: %timeit foo2(x)
100000 loops, best of 3: 8.54 µs per loop

In [10]: %timeit foo3(x)
100000 loops, best of 3: 8.4 µs per loop

xml.etree.ElementTree findall() not behaving as expected


Tag : python , By : Rik
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Simply remove the space in the XPath query b/n field and the bracket [
 t.findall('.//field[@name="tcp.option_len"]')

Python module xml.etree.ElementTree modifies xml namespace keys automatically


Tag : python , By : nseibert
Date : March 29 2020, 07:55 AM
Hope that helps You would need to register the namespaces for your xml as well as their prefixes with ElementTree before reading/writing the xml using ElementTree.register_namespace function. Example -
import xml.etree.ElementTree as ET

ET.register_namespace('','http://schemas.xxx/2004/07/Server.Facades.ImportExport')
ET.register_namespace('i','http://www.a.org')
ET.register_namespace('d3p1','http://schemas.datacontract.org/2004/07/Management.Interfaces')

tree = ET.parse("./input.xml")
tree.write("./output.xml")

Creating Dictionaries from XML Data in Python (with xml.etree.ElementTree)


Tag : python , By : mckasty
Date : March 29 2020, 07:55 AM
will help you Find element tags, and their name, value children using findall and find methods:
>>> import xml.etree.ElementTree as ET
>>>
>>> root = ET.fromstring('''<?xml version="1.0" encoding="UTF-8"?>
... <root>
...     <element>
...         <name>XYZ</name>
...         <value>789</value>
...     </element>
...     <element>
...         <name>ABC</name>
...         <value>123</value>
...     </element>
... </root>
... ''')
>>> {e.find('name').text: e.find('value').text for e in root.findall('element')}
{'XYZ': '789', 'ABC': '123'}

xml.etree.ElementTree findall


Tag : python , By : Vick Aita
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can use the contains() function, but this would only work if you would switch to lxml.etree instead of xml.etree.ElementTree which has only partial/limited XPath support:
import lxml.etree as ET

tree = ET.parse("input.xml")
root = tree.getroot()

root.xpath("./player[contains(@name, 'rob')]")
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