Is there a key for the default namespace when creating dictionary for use with xml.etree.ElementTree.findall() in Python

>>> root = ET.fromstring("<a><b>c</b></a>")
>>> root.findall("./b")
[<Element 'b' at 0x02048C90>]
>>> lst = root.findall("./b")
>>> lst[0]
<Element 'b' at 0x02048C90>

In [1]: import xml.etree.ElementTree as ET

In [2]: x = ET.fromstring('<a><b>c</b><b>d</b><b>e</b></a>')

In [3]: def foo(root):
   ...:     d = root.findall('./b')
   ...:     for  y in d:
   ...:         pass
   ...: 

In [4]: def foo1(root):
   ...:     d = root.iterfind('./b')
   ...:     for y in d:
   ...:         pass
   ...: 

In [5]: %timeit foo(x)
100000 loops, best of 3: 9.24 µs per loop

In [6]: %timeit foo1(x)
100000 loops, best of 3: 6.65 µs per loop

In [7]: def foo2(root):
   ...:     return root.findall('./b')
   ...: 

In [8]: def foo3(root):
   ...:     return list(root.iterfind('./b'))
   ...: 

In [9]: %timeit foo2(x)
100000 loops, best of 3: 8.54 µs per loop

In [10]: %timeit foo3(x)
100000 loops, best of 3: 8.4 µs per loop

 t.findall('.//field[@name="tcp.option_len"]')

import xml.etree.ElementTree as ET

ET.register_namespace('','http://schemas.xxx/2004/07/Server.Facades.ImportExport')
ET.register_namespace('i','http://www.a.org')
ET.register_namespace('d3p1','http://schemas.datacontract.org/2004/07/Management.Interfaces')

tree = ET.parse("./input.xml")
tree.write("./output.xml")

>>> import xml.etree.ElementTree as ET
>>>
>>> root = ET.fromstring('''<?xml version="1.0" encoding="UTF-8"?>
... <root>
...     <element>
...         <name>XYZ</name>
...         <value>789</value>
...     </element>
...     <element>
...         <name>ABC</name>
...         <value>123</value>
...     </element>
... </root>
... ''')
>>> {e.find('name').text: e.find('value').text for e in root.findall('element')}
{'XYZ': '789', 'ABC': '123'}

import lxml.etree as ET

tree = ET.parse("input.xml")
root = tree.getroot()

root.xpath("./player[contains(@name, 'rob')]")