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Segmentation fault when I call operator new in linux mint


Segmentation fault when I call operator new in linux mint

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Segmentation fault when I call operator new in linux mint
Tag : cpp , By : FarmerDave
Date : November 25 2020, 01:01 AM


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What is a segmentation fault on Linux?


Tag : development , By : Gilmar Souza Jr.
Date : March 29 2020, 07:55 AM
wish help you to fix your issue A segmentation fault is when your program attempts to access memory it has either not been assigned by the operating system, or is otherwise not allowed to access.
"segmentation" is the concept of each process on your computer having its own distinct virtual address space. Thus, when Process A reads memory location 0x877, it reads information residing at a different physical location in RAM than when Process B reads its own 0x877.

Using template call std::less<int>::operator() cause segmentation fault


Tag : cpp , By : Ram
Date : March 29 2020, 07:55 AM
should help you out The problem has nothing to do with std::less<>. In your first insert() call at this point:
if ( _M_keycmp(x->key, key) ) 

Segmentation fault on linux (g++) but not on Mac OS.?


Tag : cpp , By : nagre
Date : March 29 2020, 07:55 AM
Any of those help I'm not sure but I suspect the problem is that you erase an iterator and, next, you use (increment) it.
The following is the crucial part
  for (auto iter_new = new_candidates.begin(); iter_new != new_candidates.end(); iter_new++)
  {
    norm = iter_old->x -iter_new->x;
    if (norm <= CORR_MARGIN)
    {
      // [...]
      new_candidates.erase(iter_new);
    }
  }
  auto = new_candidates.begin();
  while ( iter_new != new_candidates.end() )
  {
    norm = iter_old->x -iter_new->x;
    if (norm <= CORR_MARGIN)
    {
      // [...]
      new_candidates.erase( iter_new++ );
    }
    else
      ++iter_new;
  }

Linux segmentation fault


Tag : linux , By : johntynan
Date : March 29 2020, 07:55 AM

Why C program in whch two functions call each other recursively gives segmentation fault on linux?


Tag : c , By : Thomas Gueze
Date : January 02 2021, 06:48 AM
it helps some times Each nested function call consumes some stack space for the arguments and the return address. In your code the nested function calls are unbounded, so they consume an unbounded amount of stack. Once the stack is exhausted, the program goes on to write return addresses outside the memory allocated to the process and crashes.
Depending on the compiler, turning on optimizations might help because of tail call optimization.
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