Memory structure for an array of pointers to objects (visualization)
Date : March 29 2020, 07:55 AM
To fix this issue You have one automatic variable, arr2 pointer object. The rest is on the free store. If you only delete[] arr2, you'll free the memory for the pointers, and not the objects they point to. arr2 ---+ +---------------------------------+
| | |
| | |
+----> [Position*, Position*] |
| | | |
| | +----> [9, 6] |
| v |
| [3, 7] |
+---------------------------------+
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Structure Members - Address Overlap
Date : March 29 2020, 07:55 AM
I wish this help you Because what you're doing is undefined behavior, and compilers are certainly not required to detect and report it.
This is (of course) since doing so would be very hard in general, and also because you can do the same thing "dynamically", which makes it more or less impossible to detect at compile-time.
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Matlab - Identifying objects in one image that overlap objects in another
Tag : image , By : Matt Watson
Date : March 29 2020, 07:55 AM
may help you . One thing you could do is loop through the clusters you identified in your cells binary image (conceptual, untested code): for k=1:cellnum
[~, nucnum(k)]=bwlabel(nuclei.*(cell==k));
end
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C memory overlap?
Tag : c , By : user119413
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The 16 bytes allocated for dest need to include a byte for the trailing NULL ('\0') -- since you wrote 16 bytes, you have a non-null terminated string. Since the computer you are on has the stack organized in a particular way, you are proceeding past the end of dest and then printing src. unsigned char dest[17]={0};
memcpy(dest, src, 16); // COPY
dest[16]='\0';
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Better Way to Structure Case Statements that Partially Overlap
Tag : c , By : user167963
Date : March 29 2020, 07:55 AM
Any of those help Personally, I'd probably use a helper function, and expect the compiler to appropriately inline. It seems reasonable to assume that the three shared actions form a useful conjunct, since it is invoked more than once. void BCD(void) {
B();
C();
D();
}
// ...
switch (id) {
case 1: A(); BCD(); break;
case 2: E(); BCD(); break;
// ...
}
switch (id) {
case 1: A();
goto BCD;
case 2: E();
BCD: B();
C();
D();
break;
//...
}
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