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Turning a string into list of positive and negative numbers


Turning a string into list of positive and negative numbers

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Turning a string into list of positive and negative numbers
Tag : python , By : gopal
Date : November 24 2020, 03:41 PM


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splitting a list of integers to 2 lists: one of positive numbers and the other of negative numbers - haskell


Tag : haskell , By : Nick
Date : March 29 2020, 07:55 AM
should help you out You can do this with the partition function:
import Data.List

split = partition (>=0)

Function that returns a list of the count of positive numbers and sum of negative numbers


Tag : python , By : user182548
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have a problem when I ran my code against the unit test. Any advice would be appreciated. Please find the code below: , For the case of {}, the result of manipulate_data is [0,0] try this:
def manipulate_data(data):
    if not isinstance(data, list):
        return 'Only lists allowed'

    count = 0
    sum1 = 0
    new_list = []
    for x in data:
        if x > 0:
            count += 1

        if x < 0:
            sum1 += x

    new_list.append(count)
    new_list.append(sum1)
    return new_list

import unittest

class ManipulateDataTestCases(unittest.TestCase):
  def test_only_lists_allowed(self):
    result = manipulate_data({})
    # print('result: ', result)
    self.assertEqual(result, 'Only lists allowed', msg='Invalid argument')


if __name__ == '__main__':
    unittest.main()

Pandas - Turning column of mixed positive / negative numbers to positive


Tag : python , By : AnthonyC
Date : March 29 2020, 07:55 AM
wish helps you In my dataframe I have a column containing numbers, some positive, some negative. Example , You can assign the result back to the original column:
df['Amount'] = df['Amount'].abs()
df['AbsAmount'] = df['Amount'].abs()

Converting negative numbers to positive numbers but keeping positive numbers unchanged


Tag : c , By : Elwillow
Date : March 29 2020, 07:55 AM
I wish this help you I want to apply a bitmask to a number that will mimic the absolute value function for 2's complement encoded signed 32 bit integers. So far, I have , The last part
negated = (~x + 1) & sign;
#include <stdio.h>

// assuming 32bit, 2 complement
int sign_inverse(int n)
{
    int mask = ~n & 0x80000000U;

    if(n == 0)
        mask = 0;

    return (~n + 1) | mask;
}

int main(void)
{
    int a = 5;
    int b = -4;
    int c = 54;
    int d = 0;

    printf("sign_inverse(%d) = %d\n", a, sign_inverse(a));
    printf("sign_inverse(%d) = %d\n", b, sign_inverse(b));
    printf("sign_inverse(%d) = %d\n", c, sign_inverse(c));
    printf("sign_inverse(%d) = %d\n", d, sign_inverse(d));

    return 0;
}
$ ./b 
sign_inverse(5) = -5
sign_inverse(-4) = 4
sign_inverse(54) = -54
sign_inverse(0) = 0

need to determine the positive, negative and zero numbers in program and add all the positive and negative numbers separ


Tag : java , By : jonagh
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Is the problem that you want to run the loop 10 times? You've got a count variable that you are not otherwise using. The loop should look something like:
int count=0;
while (count != 10) {
    ...
    ++count;
}
for (int count=0; count<10; ++count) {
    ...
}
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