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A `query-replace` that asks for a new replacement string for each occurrence


A `query-replace` that asks for a new replacement string for each occurrence

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A `query-replace` that asks for a new replacement string for each occurrence
Tag : emacs , By : bikefixxer
Date : November 24 2020, 03:41 PM


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Replace for entire line produces duplicate occurrence of replacement text


Tag : .net , By : Brian
Date : March 29 2020, 07:55 AM
Any of those help Simple question: why does
"x" -replace ".*", "y"
[Regex]::replace("x",".*","y")
>>> re.findall(".*","x")
['x', '']

String parsing - replace each repeated occurrence of a substring with a unique replacement


Tag : php , By : John Miller
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I am trying to parse a string. The catch is each of the variables in the string may occur more than once, and I need to replace each repeated occurrence with a unique replacement. , Try this:
preg_replace_callback("(\$([a-z]+))i",function($a) {return getRandomWordByType($a[1]);},$string);

Replace first occurrence of text using replaceText(searchPattern, replacement)


Tag : regex , By : woxorz
Date : March 29 2020, 07:55 AM
With these it helps The body.ReplaceText() function replaces all instances of a pattern, not just the first instance ( link ).
A better option may be to loop through the paragraphs to find the first with matching text, like so:
function deleteParagraph(textToRemove) {
  var body = DocumentApp.getActiveDocument().getBody();
 // gets all paragraphs as an array
  var paragraphs = body.getParagraphs()
  for (var i = 0; i < paragraphs.length; i++){
    if (paragraphs[i].getText() === textToRemove){
      paragraphs[i].clear()
      Logger.log(textToRemove + " was removed")
      //stops it looping through any more paragraphs
      break;
    }
  }
}

Matching occurrence in string with regex for value replacement?


Tag : chash , By : Tim Benninghoff
Date : March 29 2020, 07:55 AM
With these it helps I've spent some time on this problem but really need help from a regex guru. , This regex should do what you want:
\[([^]]*)]\s+[><=]+\s+(\@\w+)

How to skip the first occurrence of a pattern and replace rest of the string from second occurrence


Tag : perl , By : Jody Bannon
Date : March 29 2020, 07:55 AM
I wish this helpful for you I would like to skip the first occurrence of a pattern (_ in this example) and then substitute rest of the string including the pattern with tab. For example: , For given sample, there are various ways to solve it
$ echo 'T004_7_entry_00007_conf_01' | sed 's/\(_[^_]*\).*/\1\t/'
T004_7  
$ echo 'T004_7_entry_00007_conf_01' | perl -pe 's/_[^_]*\K.*/\t/'
T004_7  

$ echo 'T004_7_entry_00007_conf_01' | awk -F_ '{print $1 FS $2 "\t" }'
T004_7  
$ echo 'foo_:_baz_:_123_:_456' | awk -F_:_ '{print $1 FS $2 "\t" }'
foo_:_baz   
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