Removing duplicate characters in a String (user inputted keyword)

I hope this helps . I am asking for your help with sed. I need to remove duplicate underscores and underscores from beginning and end of string. , Just add ;s/__*/_/g;s/^_//;s/_$// just after g in your sed command.

To fix this issue The whole point of C++’ algorithm and container design is that the algorithms are – as far as possible – container agnostic.
So the same algorithm that works on vectors works – of course! – on strings.

std::sort(str.begin(), str.end());
str.erase(std::unique(str.begin(), str.end()), str.end());

wish help you to fix your issue How do I get the number of times the a value occurs in a string? , here is some simple code

var pattern = $("#sometextbox1").val();
var text = $("#sometextbox2").val();
var count = 1;
while(text.indexOf(patter)!==-1){
    $text = $text.replace(pattern, "");
    count++;
}

it should still fix some issue I've already converted the strings characters to ASCII and converted them values to binary but I'm wondering how to print the values of each character E.g if the user inputted "Hello" it would run as h,e,l,l,o in binary and print "frequency of l = 2" kind of thing .. I've written what I think could be used but anything after where I initialsie the array of size 256 is probably incorrect Any help would be much appreciated as to what I'm doing wrong , You can just print the frequency of characters only if it is not 0.

import java.util.Scanner;

public class test2
{
    public static void main( String[] args )
    {
        System.out.print( "Enter your sentence : " );
        Scanner sc = new Scanner( System.in );
        String name = sc.nextLine();
        sc.close();

        int[] array = new int[256];

        for ( int i = 0; i < name.length(); i++ )
        {
            char character = name.charAt( i );
            int ascii = ( int )character;
            System.out.println( character + " = " + Integer.toBinaryString( ascii ) );
            array[ascii]++;
        }

        for ( int i = 0; i < array.length; i++ )
        {
            if ( array[i] > 0 )
            {
                System.out.println( "Frequency of " + (char)i + " = " + array[i] );
            }
        }
    }
}

I wish this helpful for you Have seen people ask about length of an input but never relative to Octave. , In octav you should write the following:

x=input('enter a set of numbers', 's');