How to avoid the copy when I return

How to avoid the copy when I return

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How to avoid the copy when I return
Tag : cpp , By : RichAA
Date : November 24 2020, 05:47 AM

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Write a function to dynamically create a new copy of string and return a pointer to the new copy (C)

Tag : c , By : Ken
Date : March 29 2020, 07:55 AM
wish help you to fix your issue this is what I have so far but I can't figure out what is wrong with it
void newCopy(char *s)
  char newString = malloc(sizeof(int * strlen(s)));
  newString = s;
  return &newString;

Why does Python's copy.copy() return a object not equal to the original?

Tag : python , By : dormsbee
Date : March 29 2020, 07:55 AM
it helps some times Equality in Python for objects is checked by calling the __eq__() function.
>>> class CA:
...     def __eq__(self, other):
...             print("Equals")
...             return True
>>> c = CA()
>>> b = CA()
>>> c == b
>>> l = [1,2]
>>> l1 = [1,2]
>>> id(l)
>>> id(l1)
>>> l == l1

How to avoid copy-constructing a return value

Tag : cpp , By : John Bentley
Date : March 29 2020, 07:55 AM
I wish this help you The description in your question is pretty much correct. But it is important to understand that this is behavior of the abstract C++ machine. In fact, the canonical description of abstract return behavior is even less optimal
result is copied into a nameless intermediate temporary object of type std::string. That temporary persists after the function's return. That nameless intermediate temporary object is then copied to greeting after function returns.

Return value optimization: ho can I avoid copy construction of huge STL containers.

Tag : cpp , By : Bruce
Date : March 29 2020, 07:55 AM
Does that help It is meaningless. The type of RVO you mentioned is called named RVO (NRVO), and most compilers implement it.
Regardless, in C++11, vector has move constructors, so even if NRVO didn't apply, it'd still be moved, not copied.

copy object with objects avoiding mutation of the initial object (avoid copy references)

Tag : javascript , By : kokok13
Date : March 29 2020, 07:55 AM
I wish this help you I have a question regarding copy of object by reference , use this way:
let a = {
  "0": {
    "sortPluginSettings": {
      "columnSortType": "numeric",
      "sortingOrder": "noSort"

var b= JSON.parse(JSON.stringify(a));


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