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Extract scientific number from string


Extract scientific number from string

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Extract scientific number from string
Tag : python , By : Liviu Aileni
Date : November 24 2020, 05:44 AM


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String format: Start scientific notation with 0. for positive number, with -. for negative number


Tag : python , By : redha
Date : March 29 2020, 07:55 AM
To fix the issue you can do I want to format a list of numbers with a fixed exponential format: , How about this?
import re

# "fix" a number in exponential format
def fixexp(foo):
  # shift the decimal point
  foo = re.sub(r"(\d)\.", r".\1", foo)
  # add 0 for positive numbers
  foo = re.sub(r" \.",    r"0.",  foo)
  # increase exponent by 1
  exp = re.search(r"E([+-]\d+)", foo)
  newexp = "E{:+03}".format(int(exp.group(1))+1)
  foo = re.sub(r"E([+-]\d+)", newexp, foo)
  return foo

nums = [ -0.704411727284, -1.66021493805, 0.00964452299466, 0.0000000229380762349, -0.00000103417103118, -0.0000269314547877, 0.00140398741573 ]

# print the numbers in rows of 4
line = ""
for i in range(len(nums)):
  num = "{:18.11E}".format(nums[i])
  num = fixexp(num)
  line += num
  if (i%4 == 3 or i == len(nums)-1):
    print line
    line = ""
-.704411727284E+00-.166021493805E+010.964452299466E-020.229380762349E-07
-.103417103118E-05-.269314547877E-040.140398741573E-02

How change a number to Scientific Number and get the minimum value (Scientific Number format)


Tag : python , By : user183275
Date : March 29 2020, 07:55 AM
will help you If you need scientific notation you need to use the %e or %E format specifier
Using
awk 'BEGIN{printf("%.2E\n",0.000111309)}'
1.11E-04
akshay@db-3325:~$ python
Python 2.7.12 (default, Nov 19 2016, 06:48:10) 
[GCC 5.4.0 20160609] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import decimal
>>> '%.2E' % decimal.Decimal('0.000111309')
'1.11E-04'
>>> 
akshay@db-3325:~$ perl -e 'printf("%.2E\n",0.000111309)'
1.11E-04
akshay@db-3325:~$ printf "%.2E\n" 0.000111309
1.11E-04

perl extract string and scientific number


Tag : perl , By : Dennizzz
Date : March 29 2020, 07:55 AM
will be helpful for those in need Assuming that the format of data is always the same, something like this should work
my $line = 'capacitor #(.c(3.58782e-14)) c_1310 (vsub, vss_res);';
my ($net1, $net2, $net3) = $line =~ /\(.+\((.+)\)\)\s+(.+)\s+\((.+)\)/;

Extract scientific number from string in Java


Tag : java , By : ffmmjj
Date : March 29 2020, 07:55 AM

Convert character base scientific number into number and preserving the scientific notation in R


Tag : r , By : Santhanam
Date : March 29 2020, 07:55 AM
This might help you The problem is a floating point issue and the degree of accuracy to which R is working. It is converting 1e-14105 to numeric, it's just then approximating it to zero. See The R Inferno: Circle 1, Falling into the Floating Point Trap.
> as.numeric("1e-14105")
[1] 0
> class(as.numeric("1e-14105"))
[1] "numeric"
> 1e-14105
[1] 0
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