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Does the main window only update after a slot subroutine returns?


Does the main window only update after a slot subroutine returns?

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Does the main window only update after a slot subroutine returns?
Tag : qt , By : user171555
Date : November 24 2020, 05:44 AM


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How to add a slot to my main window in Qt builder?


Tag : qt , By : rajiv
Date : March 29 2020, 07:55 AM
Hope this helps I finally figured it out. You have to select the main window and hit F4 to add the function to the slots for the window.

How can i resize main window from slot in my class?


Tag : cpp , By : Dasharath Yadav
Date : March 29 2020, 07:55 AM
With these it helps Try to use QWidget::setGeometry.

Exit VBA Main Subroutine from Called Subroutine


Tag : excel , By : Jaya
Date : March 29 2020, 07:55 AM
it should still fix some issue To cease execution of your macro immediately, without returning to the calling procedure, you can use the End statement.

Python Bokeh: How to update a Toggle button - defined in the main - in a subroutine


Tag : python , By : Munir
Date : March 29 2020, 07:55 AM
With these it helps I think the while loop interferes the Tornado IO_loop. I advice you to use add_periodic_callback instead (Bokeh v1.1.0)
from bokeh.models import Column
from bokeh.plotting import curdoc
from bokeh.models.widgets import Button, Toggle, CheckboxGroup
import time

# def start_loop():
#     while (not button3.active) and (len(cb.active)):
#         time.sleep(1)
#         print(button3.active)
#         print(cb.active)

def check_status():
    print(button3.active)
    print(cb.active)

# button1 = Button(label = "start")
# button1.on_click(start_loop)

button2 = Button(label = "check status")
button2.on_click(check_status)

button3 = Toggle(label = "stop")
cb = CheckboxGroup(labels = ['stop'], active = [0])

curdoc().add_root(Column(button2, button3, cb))
curdoc().add_periodic_callback(check_status, 1000)

Load widget with signal-slot defintions from UI file in main window


Tag : python , By : user186831
Date : March 29 2020, 07:55 AM
I wish this help you Explanation:
When you have created the .ui you have only pointed out that there is a connection between the clicked signal and the init method of the widget, but when you load it using loadUi() and do not pass it as a second parameter a QWidget will use the base class of the design, in your case QWidget, which clearly has no "init" method throwing you that error.
# -*- coding: utf-8 -*-
import os
import sys

from PyQt5 import QtCore, QtWidgets, uic as pyuic


class Widget(QtWidgets.QWidget):
    def __init__(self, parent=None):
        super().__init__(parent)
        current_dir = os.path.dirname(os.path.realpath(__file__))
        uifile = os.path.join(current_dir, "serialTandemGUI.ui")
        pyuic.loadUi(uifile, self)

    @QtCore.pyqtSlot()
    def init(self):
        print("init")


class MainWindow(QtWidgets.QMainWindow):
    def __init__(self, parent=None):
        super().__init__(parent)
        self.form_widget = Widget()
        _widget = QtWidgets.QWidget()
        _layout = QtWidgets.QVBoxLayout(_widget)
        _layout.addWidget(self.form_widget)
        self.setCentralWidget(_widget)


if __name__ == "__main__":
    app = QtWidgets.QApplication.instance() or QtWidgets.QApplication(sys.argv)
    app.aboutToQuit.connect(app.deleteLater)

    w = MainWindow()
    w.show()

    sys.exit(app.exec_())
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