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Searching multi-dimensional vectors


Searching multi-dimensional vectors

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Searching multi-dimensional vectors
Tag : cpp , By : user103892
Date : November 24 2020, 05:44 AM


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Iterators and multi-dimensional vectors?


Tag : cpp , By : user183289
Date : March 29 2020, 07:55 AM
Any of those help vec_it->begin() dereferences vec_it, giving you a reference to the vector and then returns the result of calling begin() on that. You shouldn't dereference the result of that using * (doing so dereferences the iterator, yielding the element pointed at by that iterator, which is an int in this case; you want the iterator itself).
Your inner for loop should look like:
for(inner_it = vec_it->begin(); inner_it != vec_it->end(); ++inner_it)

How do I make multi-dimensional vectors?


Tag : cpp , By : Hugo
Date : March 29 2020, 07:55 AM
I hope this helps . It's possible, but note that you need a space between the two >s to remove the ambiguity between the right shift operator, i.e.
vector<vector<double> >
double matrix[10][10];

C++ - How are multi-dimensional vectors stored?


Tag : cpp , By : flesk
Date : March 29 2020, 07:55 AM
it fixes the issue
how much information (or which information) about the vector is stored in the address &A

How to Add two multi-dimensional std::vectors (without using operator+)?


Tag : cpp , By : user86493
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The algorithm is simple and straight-forward: , You must provide a version for Add() that works on basic data types
// Handle basic-datatypes
template<class T>
T Add(const T& x1, const T& x2)
{
  return x1 + x2;
}

// Specialisation for vectors
template<class T>
std::vector<T> Add(std::vector<T> const& v1, std::vector<T> const& v2)
{
  assert(v1.size()==v2.size());
  std::vector<T> result;
  result.reserve(v1.size());
  for(size_t i=0; i!=v1.size(); ++i)
    result.emplace_back(Add(v1[i],v2[i])); // possibly recursive
  return result;
}

multi-dimensional vectors and pointers to vectors


Tag : cpp , By : Igor Carron
Date : March 29 2020, 07:55 AM
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