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How do assembly instruction differentiate between register, memory address, immediate value or offset parameter?


How do assembly instruction differentiate between register, memory address, immediate value or offset parameter?

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How do assembly instruction differentiate between register, memory address, immediate value or offset parameter?
Tag : assembly , By : evegter
Date : November 24 2020, 05:44 AM


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How are the address of the memory and that of the register connected?(AddrConstant MIPS instruction)


Tag : development , By : dbarbot
Date : March 29 2020, 07:55 AM
wish help you to fix your issue In my computer organization course, I came across these basic MIPS instructions: , lw $t, offset($s) is encoded as
1000 11ss ssst tttt iiii iiii iiii iiii
1000 1110 0010 1000 0000 0000 0000 0100

Assembly - x86 call instruction and memory address?


Tag : assembly , By : ussballantyne
Date : March 29 2020, 07:55 AM
I hope this helps you . If you're disassembling .o object files that haven't been linked yet, the call address will just be a placeholder to be filled in by the linker.
You can use objdump -drwc -Mintel to show the relocation types + symbol names from a .o (The -r option is the key. Or -R for an already-linked shared library.)
objdump -M intel  -d rs-asmbench:
...
00000000004020a0 <.loop>:
  4020a0:       0f b6 c2                movzx  eax,dl
  4020a3:       0f b6 de                movzx  ebx,dh
   ...
  402166:       49 83 c3 10             add    r11,0x10
  40216a:       0f 85 30 ff ff ff       jne    4020a0 <.loop>

0000000000402170 <.last8>:
  402170:       0f b6 c2                movzx  eax,dl
objdump -M intel -d main.o
  ...
  a5:   31 f6                   xor    esi,esi
  a7:   e8 00 00 00 00          call   ac <main+0xac>
  ac:   4c 63 e0                movsxd r12,eax
  af:   ba 00 00 00 00          mov    edx,0x0
  b4:   48 89 de                mov    rsi,rbx
  b7:   44 89 f7                mov    edi,r14d
  ba:   e8 00 00 00 00          call   bf <main+0xbf>
  bf:   83 f8 ff                cmp    eax,0xffffffff
  c2:   75 cc                   jne    90 <main+0x90>
  ...
objdump -Mintel  -d asm-pinsrw.o:
0000000000000040 <.loop>:
  40:   0f b6 c2                movzx  eax,dl
  43:   0f b6 de                movzx  ebx,dh
  ...
 106:   49 83 c3 10             add    r11,0x10
 10a:   0f 85 30 ff ff ff       jne    40 <.loop>
0000000000000110 <.last8>:
 110:   0f b6 c2                movzx  eax,dl

Moving the memory address of a 32 bit register [esi] into an 8 bit low register in Assembly language x86


Tag : arrays , By : Kubla Khan
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further MASM infers the byte ptr [esi] operand-size based on the size of AL, and does an 8-bit load from the memory pointed to by the 32-bit pointer. The square brackets are a dereference for registers.
You could zero-extend those 8 bits to fill EAX with movzx eax, byte ptr [esi]. (Then you wouldn't need to zero eax earlier).

How is data, address and Instruction differentiated in Processor/Register/memory?


Tag : development , By : user152423
Date : March 29 2020, 07:55 AM

x86 Assembly MOV instruction - Register to Register and Memory to Memory


Tag : assembly , By : DotNetWise
Date : March 29 2020, 07:55 AM
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